답안 #384224

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
384224	2021-03-31T19:53:20 Z	SavicS	Vudu (COCI15_vudu)	C++14	140 / 140	808 ms	50124 KB

vudu

#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#include <bits/stdc++.h>

#define fi first
#define se second
#define pb push_back
#define sz(a) (int)a.size()
#define all(a) a.begin(), a.end()
#define rall(a) a.rbegin(), a.rend()
#define ff(i,a,b) for(int i=a;i<=b;i++)
#define fb(i,b,a) for(int i=b;i>=a;i--)

using namespace std;
using namespace __gnu_pbds;
typedef long long ll;
typedef pair<int,int> pii;
const int maxn = 1000005;
const int inf = 1e9 + 5;

template<typename T>
using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;

// os.order_of_key(k) the number of elements in the os less than k
// *os.find_by_order(k)  print the k-th smallest number in os(0-based)

int n;
ll P;
ll niz[maxn];

ll pref[maxn];

ll bor[4 * maxn];
void build(int v, int tl, int tr) {
	if(tl == tr) {
		bor[v] = niz[tl];
		return;
	}
	int mid = (tl + tr) / 2;
	build(v * 2, tl, mid);
	build(v * 2 + 1, mid + 1, tr);
	bor[v] = bor[v * 2] + bor[v * 2 + 1];
}

void update(int v, int tl, int tr, int pos, ll val) {
	if(tl == tr) {
		bor[v] += val;
		return;
	}
	int mid = (tl + tr) / 2;
	if(pos <= mid)update(v * 2, tl, mid, pos, val);
	else update(v * 2 + 1, mid + 1, tr, pos, val);
	bor[v] = bor[v * 2] + bor[v * 2 + 1];
}

ll kveri(int v, int tl, int tr, int l, int r) {
	if(tl > r || tr < l)return 0;
	if(tl >= l && tr <= r)return bor[v];
	int mid = (tl + tr) / 2;
	return kveri(v * 2, tl, mid, l, r) + kveri(v * 2 + 1, mid + 1, tr, l, r);
}


int main()
{
	ios::sync_with_stdio(false);
	cout.tie(nullptr);
	cin.tie(nullptr);
	cin >> n;
	ff(i,1,n)cin >> niz[i];
	cin >> P;

	ff(i,1,n)pref[i] = pref[i - 1] + niz[i];

	vector<ll> all;
	ff(i,1,n)all.pb(pref[i] - 1ll * P * i);
	sort(all(all));
	all.erase(unique(all(all)), all.end());

	auto Fnd = [&](ll x) {
		return lower_bound(all(all), x) - all.begin() + 1;
	};

	ll rez = 0;
	ff(i,1,n) {
		int x = Fnd(pref[i] - 1ll * i * P);
		if(pref[i] - 1ll * i * P >= 0)rez += 1;
		rez += kveri(1,1,n,1,x);
		update(1,1,n,x,1);
	}

	cout << rez << endl;

	return 0;
}
/**

3
1 2 3
3


// probati bojenje sahovski ili slicno

**/

Subtask #1

140.0 / 140.0

#	결과	실행 시간	메모리	Grader output
1	Correct	5 ms	748 KB	Output is correct
2	Correct	4 ms	748 KB	Output is correct
3	Correct	4 ms	748 KB	Output is correct
4	Correct	808 ms	48972 KB	Output is correct
5	Correct	412 ms	35148 KB	Output is correct
6	Correct	673 ms	45388 KB	Output is correct
7	Correct	680 ms	46540 KB	Output is correct
8	Correct	601 ms	42700 KB	Output is correct
9	Correct	763 ms	50124 KB	Output is correct
10	Correct	671 ms	45740 KB	Output is correct