# | 제출 시각 | 아이디 | 문제 | 언어 | 결과 | 실행 시간 | 메모리 |
---|---|---|---|---|---|---|---|
382518 | talant117408 | 이상한 기계 (APIO19_strange_device) | C++17 | 508 ms | 32604 KiB |
이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
/*
Code written by Talant I.D.
*/
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
using namespace __gnu_pbds;
using namespace std;
typedef long long ll;
typedef pair <int, int> pii;
typedef pair <ll, ll> pll;
typedef tree <pii, null_type, less <pii>, rb_tree_tag, tree_order_statistics_node_update> ordered_set;
#define precision(n) fixed << setprecision(n)
#define pb push_back
#define ub upper_bound
#define lb lower_bound
#define mp make_pair
#define eps (double)1e-9
#define PI 2*acos(0.0)
#define endl "\n"
#define sz(v) int((v).size())
#define all(v) v.begin(),v.end()
#define rall(v) v.rbegin(),v.rend()
#define do_not_disturb ios::sync_with_stdio(0);cin.tie(0);cout.tie(0);
#define OK cout << "OK" << endl;
const int mod = 1e9+7;
ll mode(ll a) {
a %= mod;
if (a < 0) a += mod;
return a;
}
ll subt(ll a, ll b) {
return mode(mode(a)-mode(b));
}
ll add(ll a, ll b) {
return mode(mode(a)+mode(b));
}
ll mult(ll a, ll b) {
return mode(mode(a)*mode(b));
}
ll binpow(ll a, ll b) {
ll res = 1;
while (b) {
if (b&1) res = mult(res, a);
a = mult(a, a);
b >>= 1;
}
return res;
}
void usaco(string s) {
freopen((s+".in").c_str(), "r", stdin);
freopen((s+".out").c_str(), "w", stdout);
}
ll n, a, b;
ll A(ll x) {
return (x+x/b)%a;
}
ll B(ll x) {
return x%b;
}
int main() {
do_not_disturb
//~ usaco("dirtraverse");
ll sum = 0;
cin >> n >> a >> b;
vector <pll> v(n), segs;
for (auto &to : v) cin >> to.first >> to.second;
for (auto to : v) sum += (to.second-to.first+1);
if (sum <= 1e6+7) {
set <pll> st;
for (auto to : v) {
for (ll j = to.first; j <= to.second; j++) {
st.insert(mp((j+j/b)%a, j%b));
}
}
cout << sz(st) << endl;
}
else if (b == 1) {
for (auto to : v) {
if (A(to.first) <= A(to.second)) {
segs.pb(mp(A(to.first), A(to.second)));
}
else {
segs.pb(mp(A(to.first), a-1));
segs.pb(mp(0ll, A(to.second)));
}
}
sort(all(segs));
ll ans = 0;
for (int i = 0, j = 0; i < sz(segs); i = j) {
auto l = segs[i].first, r = segs[i].second;
for (; j < sz(segs) && segs[j].first <= segs[i].second; j++) {
r = max(r, segs[j].second);
}
ans += r-l+1;
}
cout << ans << endl;
}
return 0;
}
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