Submission #382069

#	Time	Username	Problem	Language	Result	Execution time	Memory
382069		vishesh312	Untitled (POI11_tem)	C++17	50 / 100	1098 ms	16364 KiB

Main

#include "bits/stdc++.h"
using namespace std;
/*
#include <ext/pb_ds/assoc_container.hpp>
using namespace __gnu_pbds;
using ordered_set = tree<int, null_type, less<int>, rb_tree_tag, tree_order_statistics_node_update>;
*/

#define all(x) begin(x), end(x)
#define sz(x) (int)x.size()

using ll = long long;
const int mod = 1e9+7;

const int mxN = 1e6;
int mn[mxN], mx[mxN];

struct SegTree {
    int n;
    int t[mxN * 4];
    void build(int v, int tl, int tr) {
        if (tl == tr) {
            t[v] = mn[tl];
        } else {
            int tm = (tl + tr) / 2;
            build(v*2, tl, tm);
            build(v*2+1, tm+1, tr);
            t[v] = max(t[v*2], t[v*2+1]);
        }
    }
    int query(int v, int tl, int tr, int l, int r) {
        if (l > r) return -1e9;
        if (l == tl and r == tr) return t[v];
        int tm = (tl + tr) / 2;
        return max(query(v*2, tl, tm, l, min(r, tm)), query(v*2+1, tm+1, tr, max(l, tm+1), r));
    }
    SegTree(int _n) {
        n = _n;
        build(1, 0, n-1);
    }
    int query(int l, int r) {
        return query(1, 0, n-1, l, r);
    }
};

void solve(int tc) {
    int n;
    cin >> n;
    for (int i = 0; i < n; ++i) {
        cin >> mn[i] >> mx[i];
    }
    SegTree seg(n);
    int lo = 0, hi = n-1;
    int m = -1e9;
    int ans = 0;
    for (int i = 0; i < n; ++i) {
        if (mx[i] < m) {
            ++lo;
            hi = i;
            while (lo < hi) {
                int mid = (lo + hi) / 2;
                int q = seg.query(mid, i);
                if (mx[i] < q) lo = mid+1;
                else hi = mid;
            }
            m = seg.query(lo, i);
        }
        m = max(m, mn[i]);
        ans = max(ans, i - lo + 1);
    }
    cout << ans << '\n';
}

signed main() {
    ios_base::sync_with_stdio(false); cin.tie(NULL);
    int tc = 1;
    //cin >> tc;
    for (int i = 1; i <= tc; ++i) solve(i);
    return 0;
}

• Subtask 1: 8 / 8
• Subtask 2: 8 / 8
• Subtask 3: 8 / 8
• Subtask 4: 8 / 8
• Subtask 5: 0 / 8
• Subtask 6: 0 / 8
• Subtask 7: 0 / 8
• Subtask 8: 0 / 8
• Subtask 9: 9 / 9
• Subtask 10: 9 / 9
• Subtask 11: 0 / 9
• Subtask 12: 0 / 9