이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#define ff first
#define ss second
using namespace std;
typedef pair<int, int> pii;
const int maxn = 1e5+10;
int a[maxn];
int ql[maxn], qr[maxn];
struct LazySegmentTree
{
int tree[4*maxn];
bool lazy[4*maxn];
void build(int node, int l, int r)
{
tree[node] = r-l+1, lazy[node] = 0;
if (l == r) return;
int mid = (l+r)>>1;
build(2*node, l, mid); build(2*node+1, mid+1, r);
}
void flush(int node, int l, int r)
{
if (!lazy[node]) return;
if (l != r) lazy[2*node] = lazy[2*node+1] = 1;
tree[node] = 0;
lazy[node] = 0;
}
void upd(int node, int l, int r, int a, int b)
{
flush(node, l, r);
if (l > b || r < a) return;
if (l >= a && r <= b)
{
lazy[node] = 1;
flush(node, l, r);
return;
}
int mid = (l+r)>>1;
upd(2*node, l, mid, a, b); upd(2*node+1, mid+1, r, a, b);
tree[node] = tree[2*node] + tree[2*node+1];
}
int get(int node, int l, int r, int p)
{
flush(node, l, r);
if (l == r) return l;
int mid = (l+r)>>1;
flush(2*node, l, mid); flush(2*node+1, mid+1, r);
if (tree[2*node] >= p) return get(2*node, l, mid, p);
return get(2*node+1, mid+1, r, p-tree[2*node]);
}
} seg;
int ans_l[maxn], ans_r[maxn];
struct SegmentTree
{
vector<int> tree[4*maxn][2];
void upd(int node, int l, int r, int a, int b)
{
if (l > b || r < a) return;
if (l >= a && r <= b)
{
tree[node][0].push_back(-a);
tree[node][1].push_back(b);
return;
}
int mid = (l+r)>>1;
upd(2*node, l, mid, a, b); upd(2*node+1, mid+1, r, a, b);
}
int getl(int node, int l, int r, int pos, int k)
{
int mid = (l+r)>>1;
int v = 1;
if (l != r)
{
v = (pos <= mid ? getl(2*node, l, mid, pos, k) : getl(2*node+1, mid+1, r, pos, k));
}
if (!v) return 0;
if (tree[node][0].size() == 0 || -tree[node][0].back() > k)
{
ans_l[pos] += tree[node][0].size();
return 1;
}
int x = (int)(lower_bound(tree[node][0].begin(), tree[node][0].end(), -k) - tree[node][0].begin());
ans_l[pos] += x;
return 0;
}
int getr(int node, int l, int r, int pos, int k)
{
int mid = (l+r)>>1;
int v = 1;
if (l != r)
{
v = (pos <= mid ? getr(2*node, l, mid, pos, k) : getr(2*node+1, mid+1, r, pos, k));
}
if (!v) return 0;
if (tree[node][1].size() == 0 || tree[node][1].back() < k)
{
ans_r[pos] += tree[node][1].size();
return 1;
}
int x = (int)(lower_bound(tree[node][1].begin(), tree[node][1].end(), k) - tree[node][1].begin());
ans_r[pos] += x;
return 0;
}
} seg2;
int GetBestPosition(int n, int q, int R, int *K, int *S, int *E)
{
for (int i = 0; i < n-1; i++)
a[i+1] = K[i];
for (int i = 0; i < q; i++)
ql[i+1] = S[i]+1, qr[i+1] = E[i]+1;
seg.build(1, 1, n);
for (int i = 1; i <= q; i++)
{
int l = (ql[i] == 1 ? 1 : seg.get(1, 1, n, ql[i]-1)+1);
int r = seg.get(1, 1, n, qr[i]);
if (l <= r-1) seg.upd(1, 1, n, l, r-1);
seg2.upd(1, 1, n, l, r);
}
int prim = 0;
for (int i = 1; i <= n; i++)
{
seg2.getl(1, 1, n, i, prim);
if (a[i] > R) prim = i;
}
prim = n+1;
for (int i = n; i >= 1; i--)
{
seg2.getr(1, 1, n, i, prim);
if (a[i-1] > R) prim = i;
}
int best = 1, mx = 0;
for (int i = 1; i <= n; i++)
if (min(ans_l[i], ans_r[i]) > mx)
best = i, mx = min(ans_l[i], ans_r[i]);
return best-1;
}
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