This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
 
using namespace std;
 
typedef long long ll;
typedef long double ld;
 
typedef vector<int> vi;
typedef vector<ll> vll;
 
typedef vector<vi> vvi;
typedef vector<vll> vvll;
 
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
 
typedef vector<pii> vpii;
typedef vector<pll> vpll;
 
typedef vector<vpii> vvpii;
typedef vector<vpll> vvpll;
 
#define pb push_back
#define mp make_pair
#define all(x) (x).begin(), (x).end()
#define rall(x) (x).rbegin(), (x).rend()
#define sz(x) (int)(x).size()
#define fi first
#define se second
 
template<class T> bool ckmin(T &a, const T &b) {return a > b ? a = b, 1 : 0;}
template<class T> bool ckmax(T &a, const T &b) {return a < b ? a = b, 1 : 0;}
 
void __print(int x) {cerr << x;}
void __print(long long x) {cerr << x;}
void __print(double x) {cerr << x;}
void __print(long double x) {cerr << x;}
void __print(char x) {cerr << '\'' << x << '\'';}
void __print(const string &x) {cerr << '\"' << x << '\"';}
void __print(bool x) {cerr << (x ? "true" : "false");}
 
template<typename T, typename V>
void __print(const pair<T, V> &x) {cerr << '{'; __print(x.first); cerr << ','; __print(x.second); cerr << '}';}
template<typename T>
void __print(const T &x) {int f = 0; cerr << '{'; for(auto z : x) cerr << (f++ ? "," : ""), __print(z); cerr << "}";}
void _print() {cerr << "]\n";}
template <typename T, typename... V>
void _print(T t, V... v) {__print(t); if(sizeof...(v)) cerr << ", "; _print(v...);}
 
#ifdef ljuba
#define dbg(x...) cerr << "LINE(" << __LINE__ << ") -> " << "[" << #x << "] = ["; _print(x)
#else
#define dbg(x...)
#endif
 
const char nl = '\n';
const int MOD = 1e9 + 7;
const int p = 31;
inline int mul(int a, int b) {
    return (a * 1LL * b) % MOD;
}
inline int add(int a, int b) {
    return (a + b) % MOD;
}
inline int sub(int a, int b) {
    return (a - b + MOD) % MOD;
}
void solve() {
    string s;
    cin >> s;
    int n = sz(s);
    int tren = p;
    vi hsh(n+1);
    for(int i = 0; i < n; ++i) {
        hsh[i+1] = add(hsh[i], mul(tren, (s[i]-'a'+1)));
        tren = mul(tren, p);
    }
    vi inv(n+1);
    inv[0] = 1;
    for(int i = 1; i <= n; ++i) {
        inv[i] = mul(inv[i-1], 129032259);
    }
    int ans = 0;
    int posl = 1;
    int posl2 = n;
    for(int i = 1; i <= n / 2; ++i) {
        int hes1 = mul(sub(hsh[i], hsh[posl-1]), inv[posl-1]);
        int hes2 = mul(sub(hsh[posl2], hsh[n-i]), inv[n-i]);
        if(hes1 == hes2) {
            ans += 2;
            posl = i + 1;
            posl2 = n - i;
        }
    }
    dbg(posl, posl2);
    ans += (posl <= posl2);
    cout << ans << nl;
}
 
int main() {
    ios::sync_with_stdio(0);
    cin.tie(0);
    cout.tie(0);
    int testCases = 1;
    cin >> testCases;
    while(testCases--)
        solve();
 
}
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