제출 #364653

#제출 시각아이디문제언어결과실행 시간메모리
364653bigDuck공장들 (JOI14_factories)C++14
0 / 100
27 ms12396 KiB
#include "factories.h" #include<bits/stdc++.h> using namespace std; #define INIT ios_base :: sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL);mt19937 rng(chrono::steady_clock::now().time_since_epoch().count()); #define mp make_pair #define pb push_back #define ft first #define sc second #define ll long long #define pii pair<int, int> #define count_bits __builtin_popcount int anc[500010][21]; vector<pii> g[500010]; ll d[500010]; int tmp=0; int ent[500010], ex[500010]; int n; void dfs(int s){ tmp++; ent[s]=tmp; for(pii pr:g[s]){ int u=pr.ft, c=pr.sc; if(u==anc[s][0]){continue;} d[u]=d[s]+c; anc[u][0]=s; dfs(u); } tmp++; ex[s]=tmp; return; } void Init(int N, int A[], int B[], int D[]) { n=N; for(int i=0; i<(n-1); i++){ g[A[i]+1 ].pb({B[i]+1, D[i]}); g[B[i]+1 ].pb({A[i]+1, D[i]}); } dfs(1); for(int i=1; i<=20; i++){ for(int j=1; j<=n; j++){ anc[j][i]=anc[anc[j][i-1] ][i-1]; } } return; } bool is_anc(int u, int v){ return (ent[u]<=ent[v]) && (ex[u]>=ex[v]); } int lca(int u, int v){ if( is_anc(u, v) ){ return u; } int cr=u; for(int i=20; i>=0; i--){ if( (anc[cr][i]!=(0)) && (!is_anc(anc[cr][i], v)) ){ cr=anc[cr][i]; } } return anc[cr][0]; } bool v[500010]; int mrk[5010]; ll d1[5010]; ll dfs0(int s){ ll res=1e18; //cout<<"x"<<flush; if(mrk[s]==1){ d1[s]=0; } else{ if(d1[s]==0){ d1[s]=1e18;} } //cout<<s<<" "<<mrk[s]<<" "<<d1[s]<<"\n"; v[s]=true; for(pii pr:g[s]){ int u=pr.ft, c=pr.sc; if(v[u]){continue;} res=min(res, dfs0(u)); d1[s]=min(d1[u]+c, d1[s]); } v[s]=false; if(s==1){ v[s]=true; for(pii pr:g[s]){ int u=pr.ft, c=pr.sc; if(v[u]){continue;} d1[u]=min(d1[s]+c, d1[u]); res=min(res, dfs0(u)); d1[s]=min(d1[u]+c, d1[s]); } v[s]=false; } if(mrk[s]==2){ res=min(res, d1[s]); } //return res; return res; } long long Query(int S, int X[], int T, int Y[]) { ll res=1e18; if( n<=5000 ){ for(int i=0; i<S; i++){ mrk[X[i]+1 ]=1; } //ll res=1e18; for(int i=0; i<T; i++){ mrk[Y[i]+1 ]=2; } //res=min(res, (dfs0(1)).ft); ll r=dfs0(1); res=min(res, r); for(int i=0; i<S; i++){ mrk[X[i]+1 ]=0; } //ll res=1e18; for(int i=0; i<T; i++){ mrk[Y[i]+1 ]=0; } for(int i=1;i<=n; i++){ d1[i]=0; } } else{ for(int i=0; i<S; i++){ for(int j=0; j<T; j++){ int u=X[i]+1, v=Y[j]+1; int anc=lca(u, v); res=min(res, d[u]+d[v]-2*d[anc]); } } } return res; }
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