제출 #362326

#제출 시각아이디문제언어결과실행 시간메모리
362326mohamedsobhi777Restore Array (RMI19_restore)C++14
7 / 100
14 ms640 KiB
#include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #pragma GCC optimize("-Ofast") //#pragma GCC optimize("trapv") #pragma GCC target("sse,sse2,sse3,ssse3,sse4,sse4.2,popcnt,abm,mmx,avx2,tune=native") #pragma GCC optimize("-ffast-math") #pragma GCC optimize("-funroll-loops") using namespace std; using namespace __gnu_pbds; #define vi vector<int> #define vll vector<ll> #define vii vector<pair<int, int>> #define vvi vector<vi> #define vvii vector<vii> #define pii pair<int, int> #define pll pair<ll, ll> #define loop(_) for (int __ = 0; __ < (_); ++__) #define forn(i, n) for (int i = 0; i < n; ++i) #define pb push_back #define f first #define s second #define sz(_) ((int)_.size()) #define all(_) _.begin(), _.end() #define uni(_) unique(_) #define lb lower_bound #define ub upper_bound #define si set<int> #define ms multiset<int> #define qi queue<int> #define pq prioriry_queue<int> #define mi map<int, int> #define inc(i, l, r) for (int i = l; i <= r; i++) #define dec(i, l, r) for (int i = l; i >= r; i--) using lll = __int128; using ll = long long; using ld = long double; const int N = 1e5 + 7; const ll mod = 1e9 + 7; const ll inf = 2e18; auto ra = [] {char *p = new char ; delete p ; return ll(p) ; }; mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count() * (ra() | 1)); typedef tree<pii, null_type, less<pii>, rb_tree_tag, tree_order_statistics_node_update> os; int n, k; int L[N], R[N], K[N], V[N]; int main() { ios_base::sync_with_stdio(0); cin.tie(0); #ifndef ONLINE_JUDGE #endif cin >> n >> k; for (int i = 0; i < k; ++i) { cin >> L[i] >> R[i] >> K[i] >> V[i]; } // just bruteforce for (int i = 0; i < (1 << n); ++i) { bool ok = 1; vi ve(n, 0); ve[0] = (i & 1); for (int j = 1; j < n; ++j) { ve[j] = (ve[j - 1] + (!!(i & (1 << j)))); } auto get = [&](int l, int r) -> int { return ve[r] - (l ? ve[l - 1] : 0); }; for (int j = 0; j < k; ++j) { int len = R[j] - L[j] + 1; if (V[j] == 0) { if (get(L[j], R[j]) > len - K[j]) { ok = 0; break; } } else { if (get(L[j], R[j]) <= len - K[j]) { ok = 0; break; } } } if (ok) { for (int j = 0; j < n; ++j) { cout << !!(i & (1 << j)) << " "; } exit(0); } } cout << -1; return 0; }
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