제출 #343851

#제출 시각아이디문제언어결과실행 시간메모리
343851AmineWeslati앵무새 (IOI11_parrots)C++14
98 / 100
9 ms1560 KiB
//Never stop trying /*#pragma GCC target ("avx2") #pragma GCC optimize ("Ofast") #pragma GCC optimization ("O3") #pragma GCC optimization ("unroll-loops")*/ #include "bits/stdc++.h" using namespace std; #define boost ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0) typedef long long ll; typedef string str; typedef double db; typedef long double ld; typedef pair<int, int> pi; #define fi first #define se second typedef vector<int> vi; typedef vector<pi> vpi; typedef vector<str> vs; typedef vector<ld> vd; #define pb push_back #define eb emplace_back #define sz(x) (int)x.size() #define all(x) begin(x), end(x) #define rall(x) rbegin(x), rend(x) #define endl "\n" #define FOR(i,a,b) for (int i = (a); i < (b); ++i) #define ROF(i,a,b) for (int i = (b)-1; i >= (a); --i) const int MOD = 1e9 + 7; //998244353 const ll INF = 1e18; const int MX = 2e5 + 10; const int nx[4] = {0, 0, 1, -1}, ny[4] = {1, -1, 0, 0}; //right left down up template<class T> using V = vector<T>; template<class T> bool ckmin(T& a, const T& b) { return a > b ? a = b, 1 : 0; } template<class T> bool ckmax(T& a, const T& b) { return a < b ? a = b, 1 : 0; } ll cdiv(ll a, ll b) { return a / b + ((a ^ b) > 0 && a % b); } // divide a by b rounded up //constexpr int log2(int x) { return 31 - __builtin_clz(x); } // floor(log2(x)) mt19937 rng(chrono::system_clock::now().time_since_epoch().count()); //mt19937_64 rng(chrono::system_clock::now().time_since_epoch().count()); ll random(ll a, ll b){ return a + rng() % (b - a + 1); } #ifndef LOCAL #define cerr if(false) cerr #endif #define dbg(x) cerr << #x << " : " << x << endl; #define dbgs(x,y) cerr << #x << " : " << x << " / " << #y << " : " << y << endl; #define dbgv(v) cerr << #v << " : " << "[ "; for(auto it : v) cerr << it << ' '; cerr << ']' << endl; #define here() cerr << "here" << endl; void IO() { #ifdef LOCAL freopen("input.txt", "r", stdin); freopen("output.txt", "w", stdout); #endif } #ifndef LOCAL #include "encoder.h" #include "encoderlib.h" #endif #ifdef LOCAL void send(int x){ bitset<8> bs(x); cout << bs << endl; } #endif void encode(int N, int M[]){ bitset<512>b; int idx=0; FOR(i,0,N){ ROF(j,0,8){ b[idx]=(((M[i])>>(j))&1); idx++; } } vi cnt(4,0),cnt2(4,0); for(int i=0; i<idx; i+=2){ cnt[b[i]*2+b[i+1]]++; cnt2[3-(b[i]*2+b[i+1])]++; } int plan=1; if(cnt[1]+2*cnt[2]+3*cnt[3]<cnt2[1]+2*cnt2[2]+3*cnt2[3]) plan=0; for(int i=0; i<idx; i+=2){ int x=b[i]*2+b[i+1]; if(plan) x=3-x; while(x--) send(i/2); } if(plan){ int x=4; while(x--) send(255); } } #ifdef LOCAL int main() { boost; IO(); int N; cin>>N; int X[N]; FOR(i,0,N){ str s; cin>>s; int val=0; FOR(idx,0,8){ val*=2; val+=s[idx]-'0'; } X[i]=val; } encode(N,X); return 0; } #endif /* 4 01010011 10111111 11100000 01010101 */ /* Careful!!! .Array bounds .Infinite loops .Uninitialized variables / empty containers .Multisets are shit Some insights: .Binary search .Graph representation .Write brute force code .Change your approach */
//Never stop trying /*#pragma GCC target ("avx2") #pragma GCC optimize ("Ofast") #pragma GCC optimization ("O3") #pragma GCC optimization ("unroll-loops")*/ #include "bits/stdc++.h" using namespace std; #define boost ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0) typedef long long ll; typedef string str; typedef double db; typedef long double ld; typedef pair<int, int> pi; #define fi first #define se second typedef vector<int> vi; typedef vector<pi> vpi; typedef vector<str> vs; typedef vector<ld> vd; #define pb push_back #define eb emplace_back #define sz(x) (int)x.size() #define all(x) begin(x), end(x) #define rall(x) rbegin(x), rend(x) #define endl "\n" #define FOR(i,a,b) for (int i = (a); i < (b); ++i) #define ROF(i,a,b) for (int i = (b)-1; i >= (a); --i) const int MOD = 1e9 + 7; //998244353 const ll INF = 1e18; const int MX = 2e5 + 10; const int nx[4] = {0, 0, 1, -1}, ny[4] = {1, -1, 0, 0}; //right left down up template<class T> using V = vector<T>; template<class T> bool ckmin(T& a, const T& b) { return a > b ? a = b, 1 : 0; } template<class T> bool ckmax(T& a, const T& b) { return a < b ? a = b, 1 : 0; } ll cdiv(ll a, ll b) { return a / b + ((a ^ b) > 0 && a % b); } // divide a by b rounded up //constexpr int log2(int x) { return 31 - __builtin_clz(x); } // floor(log2(x)) mt19937 rng(chrono::system_clock::now().time_since_epoch().count()); //mt19937_64 rng(chrono::system_clock::now().time_since_epoch().count()); ll random(ll a, ll b){ return a + rng() % (b - a + 1); } #ifndef LOCAL #define cerr if(false) cerr #endif #define dbg(x) cerr << #x << " : " << x << endl; #define dbgs(x,y) cerr << #x << " : " << x << " / " << #y << " : " << y << endl; #define dbgv(v) cerr << #v << " : " << "[ "; for(auto it : v) cerr << it << ' '; cerr << ']' << endl; #define here() cerr << "here" << endl; void IO() { #ifdef LOCAL freopen("input.txt", "r", stdin); freopen("output.txt", "w", stdout); #endif } #ifndef LOCAL #include "decoder.h" #include "decoderlib.h" #endif #ifdef LOCAL void output(int x){ bitset<8>bs(x); cout << bs << endl; } #endif void decode(int N, int L, int X[]){ vi cnt(256,0); FOR(i,0,L) cnt[X[i]]++; int plan=0; if(cnt[255]>3){ cnt[255]-=4; plan=1; } bitset<512> b; FOR(i,0,N*4){ int x=cnt[i]; if(plan) x=3-x; dbg(x) b[i*2+1]=x&1; x/=2; b[i*2]=x; } for(int i=0; i<N*8; i+=8){ int ans=0; FOR(j,i,i+8){ ans*=2; ans+=b[j]; } output(ans); } } #ifdef LOCAL int main() { boost; IO(); int N,K; cin>>N>>K; int v[K]; FOR(i,0,K){ str s; cin>>s; int val=0; FOR(idx,0,8) val+=(s[idx]-'0')*((1)<<(7-idx)); v[i]=val; } decode(N,K,v); return 0; } #endif /* Careful!!! .Array bounds .Infinite loops .Uninitialized variables / empty containers .Multisets are shit Some insights: .Binary search .Graph representation .Write brute force code .Change your approach */
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