Submission #340139

#TimeUsernameProblemLanguageResultExecution timeMemory
340139blueBali Sculptures (APIO15_sculpture)C++11
21 / 100
154 ms508 KiB
#include <iostream> #include <vector> using namespace std; //Subtask 1, 2, 3, 4: N <= 100 /* For the worst beauty value, we want to first of all make the most significant bit as small as possible. Loop through all the bits: log(max_N) = 32 Loop through all the positions: N = 100 Loop through all the previous choices: N = 100 Loop through all the choices of x (a<x<b)= 100 Grand total = 32e6 = 3e7 √ */ long long pow2[40]; // arr size, limits on x, sculpture values long long solve_1(long long N, long long A, long long B, vector<long long> Y) { long long dp[N+1][B+1]; //is it possible to partition 1..i into j groups such that no group has value v & 1<<bit == 1 long long res = pow2[39] - 1, temp; long long curr_res = 0; for(long long bit = 38; bit >= 0; bit--) { for(long long i = 0; i <= N; i++) for(long long x = 0; x <= B; x++) dp[i][x] = 0; res -= pow2[bit]; dp[0][0] = 1; for(long long i = 1; i <= N; i++) { dp[i][1] = (Y[i] | res) <= res; for(long long x = 2; x <= B; x++) { for(long long j = 0; j < i; j++) { if(((Y[i] - Y[j]) | res) > res) continue; if(!dp[j][x-1]) continue; dp[i][x] |= dp[j][x-1]; } } } temp = 0; for(long long x = A; x <= B; x++) temp |= dp[N][x]; if(!temp) res += pow2[bit]; } return res; } /* ----------------------------------------------------- */ //Subtask 3, 5: A = 1 /* We start out with Y[1] + ... Y[N] We can make a cut anywhere between i and i+1, which turns a+b into a | b We can make at most B cuts. Find the minimum value. (a | b) | c = a | b | c only difference is here. 00 10 01 11 + 0 1 1 2 | 0 1 1 1 Greedy? 8 1 2 1 5 4 1000, 0001, 0010, 0001, 0101, 0100 Prefsum: 8 9 11 12 17 21 001000, 001001, 001011, 001100, 010001, 010101 */ long long solve_2(long long N, long long B, vector<long long> Y) { long long dp[N+1]; //minimum number of partitions of 1..i such that no group has value v & 1<<bit == 1 long long res = pow2[39] - 1, temp; long long curr_res = 0; for(long long bit = 38; bit >= 0; bit--) { res -= pow2[bit]; dp[0] = 0; for(long long i = 1; i <= N; i++) { dp[i] = B+1; for(long long j = 0; j < i; j++) { if(((Y[i] - Y[j]) | res) > res) continue; dp[i] = min(dp[i], dp[j]+1); } } if(dp[N] > B) res += pow2[bit]; } return res; } int main() { pow2[0] = 1; for(int i = 1; i < 40; i++) pow2[i] = pow2[i-1] * 2; long long N, A, B; cin >> N >> A >> B; vector<long long> Y(N+1); Y[0] = 0; for(long long i = 1; i <= N; i++) { cin >> Y[i]; Y[i] += Y[i-1]; } // if(N <= 100) cout << solve_1(N, A, B, Y) << '\n'; // else cout << solve_2(N, B, Y) << '\n'; //A = 1 cout << solve_2(N, B, Y) << '\n'; }

Compilation message (stderr)

sculpture.cpp: In function 'long long int solve_1(long long int, long long int, long long int, std::vector<long long int>)':
sculpture.cpp:24:15: warning: unused variable 'curr_res' [-Wunused-variable]
   24 |     long long curr_res = 0;
      |               ^~~~~~~~
sculpture.cpp: In function 'long long int solve_2(long long int, long long int, std::vector<long long int>)':
sculpture.cpp:79:35: warning: unused variable 'temp' [-Wunused-variable]
   79 |     long long res = pow2[39] - 1, temp;
      |                                   ^~~~
sculpture.cpp:80:15: warning: unused variable 'curr_res' [-Wunused-variable]
   80 |     long long curr_res = 0;
      |               ^~~~~~~~
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...