이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include "doll.h"
#include <vector>
#include <iostream>
using namespace std;
//
// void answer(vector<int> C, vector<int> X, vector<int> Y)
// {
// cout << C.size() << ' ' << X.size() << '\n';
// for(int i = 0; i < C.size(); i++) cout << C[i] << '\n';
// for(int i = 0; i < X.size(); i++) cout << X[i] << ' ' << Y[i] << '\n';
// }
void create_circuit(int M, vector<int> A)
{
vector<int> C(M+1, -1);
vector<int> X, Y;
int N = A.size();
C[0] = A[0];
if(N == 1)
{
C[A[0]] = 0;
answer(C, X, Y);
return;
}
int p;
for(p = 1; 2*(1 << p) < N; p++); //1<<p is the size of the last row of the binary tree (1<<p) <= N <= (1<<p+1)
X = vector<int>( (1 << (p+1)) - 1 , -1);
Y = vector<int>( (1 << (p+1)) - 1 , -1);
for(int i = 2; i < (1 << (p+1)); i++)
{
if(i % 2 == 0) X[i/2 - 1] = -i;
else Y[i/2 - 1] = -i;
}
// cout << "0 " << C[0] << '\n';
// for(int i = 1; i < (1 << (p+1)); i++) cout << i << ' ' << X[i-1] << ' ' << Y[i-1] << '\n';
for(int i = (1 << (p+1)); i < (1 << (p+2)); i++)
{
// cout << "switch = " << i << '\n';
if(i - (1 << (p+1)) + 1 < N)
{
if(i % 2 == 0) X[i/2 - 1] = A[i - (1 << (p+1)) + 1];
else Y[i/2 - 1] = A[i - (1 << (p+1)) + 1];
}
else if(i == (1 << (p+2))-1)
{
Y[i/2 - 1] = 0;
}
else
{
if(i % 2 == 0) X[i/2 - 1] = -1;
else Y[i/2 - 1] = -1;
}
}
answer(C, X, Y);
}
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