제출 #337466

#제출 시각아이디문제언어결과실행 시간메모리
337466syyNaan (JOI19_naan)C++17
29 / 100
462 ms78060 KiB
#include <bits/stdc++.h> using namespace std; typedef long long ll; typedef long double ld; #define FOR(i, a, b) for(ll i = (ll)a; i <= (ll)b; i++) #define DEC(i, a, b) for(ll i = (ll)a; i >= (ll)b; i--) typedef pair<ll, ll> pi; typedef pair<pi, ll> pii; typedef pair<ll, pi> ipi; typedef pair<pi, pi> pipi; #define mp make_pair #define f first #define s second typedef vector<ll> vi; typedef vector<pi> vpi; typedef vector<pii> vpii; #define pb push_back #define pf push_front #define all(v) v.begin(), v.end() #define size(v) (ll) v.size() #define disc(v) sort(all(v)); v.resize(unique(all(v)) - v.begin()); #define INF (ll) 1e9 + 100 #define LLINF (ll) 1e18 #define fastio ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0) #define sandybridge __attribute__((optimize("Ofast"), target("arch=sandybridge"))) mt19937 rng(chrono::steady_clock::now().time_since_epoch().count()); //can be used by calling rng() or shuffle(A, A+n, rng) inline ll rand(ll x, ll y) { ++y; return (rng() % (y-x)) + x; } //inclusivesss struct frac { ll n, d; frac(ll x = 0, ll num = 0, ll den = 1) { // default to 0 assert(den != 0); // no divide by 0 n = num; d = den; if (d < 0) d = -d, n = -n; n += x * d; } frac operator+(frac a) { return frac(0, n*a.d + a.n*d, d*a.d); } frac operator+(ll a) { return frac(0, n + a*d, d); } frac operator-() { return frac(0, -n, d); } frac operator-(frac a) { return frac(0, n*a.d - a.n*d, d*a.d); } frac operator-(ll a) { return frac(0, n - a*d, d); } frac operator*(frac a) { return frac(0, n*a.n, d*a.d); } frac operator*(ll a) { return frac(0, n*a, d); } frac operator/(frac a) { return frac(0, n*a.d, a.n*d); } frac operator/(ll a) { return frac(0, n, a*d); } bool operator>(ll a) { return n > a*d; } bool operator<(frac a) const { return n*a.d < a.n*d; } void print() { cout << n << " " << d << "\n"; } }; ll n, l, arr[2005][2005]; bool vis[2005]; vector<pair<frac, ll>> v[2005]; vi ans; bool cmp(pair<frac, ll> a, pair<frac, ll> b) { return a.f < b.f; } int main() { fastio; cin >> n >> l; FOR(i, 1, n) FOR(j, 1, l) cin >> arr[i][j]; FOR(i, 1, n) { ll tot = 0; FOR(j, 1, l) tot += arr[i][j]; ll idx = 0, cur = 0; FOR(j, 1, n-1) { //find prefix of naan with j/n value while (idx < l and frac(0, j*tot, n) > cur + arr[i][idx+1]) cur += arr[i][++idx]; v[j].pb(mp(((frac(0, j*tot, n) - cur) / arr[i][idx+1]) + idx, i)); } } FOR(i, 1, n-1) { sort(all(v[i]), cmp); ll idx = 0; while (vis[v[i][idx].s]) idx++; ans.pb(v[i][idx].s); vis[v[i][idx].s] = 1; v[i][idx].f.print(); } for (auto it:ans) cout << it << " "; FOR(i, 1, n) if (!vis[i]) cout << i; }
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