Submission #328925

#	Time	Username	Problem	Language	Result	Execution time	Memory
328925		dolphingarlic	Examination (JOI19_examination)	C++14	2 / 100	3068 ms	14896 KiB

examination

#include <bits/stdc++.h>
#pragma GCC optimize("unroll-loops")
#pragma GCC optimize("O3")
#pragma GCC target("sse4,avx2,fma,avx")
typedef long long ll;
using namespace std;

const int B = 750;

int n, q;
ll s[100001], t[100001], sums[100001], sum_ptr[100001];
pair<ll, int> by_s[100001], by_t[100001];
tuple<ll, ll, ll, int> queries[100001];
int bit[100001];
int ans[100001];

void update(int pos, int val) {
    for (; pos <= n; pos += pos & -pos) bit[pos] += val;
}

int query(int l, int r) {
    int ans = 0;
    for (; r; r -= r & -r) ans += bit[r];
    for (l--; l; l -= l & -l) ans -= bit[l];
    return ans;
}

int main() {
    ios_base::sync_with_stdio(0);
    cin.tie(0);
    cin >> n >> q;
    for (int i = 0; i < n; i++) {
        cin >> s[i] >> t[i];
        sums[i] = s[i] + t[i];
        by_s[i] = {s[i], i};
        by_t[i] = {t[i], i};
    }
    sort(sums, sums + n);
    for (int i = 0; i < n; i++) {
        sum_ptr[i] = lower_bound(sums, sums + n, s[i] + t[i]) - sums + 1;
    }
    sort(by_s, by_s + n);
    sort(by_t, by_t + n);
    for (int i = 0; i < q; i++) {
        ll a, b, c;
        cin >> a >> b >> c;
        c = lower_bound(sums, sums + n, c) - sums + 1;
        queries[i] = {a, b, c, i};
    }
    sort(queries, queries + q, greater<tuple<ll, ll, ll, int>>());

    unordered_map<int, int> good_cnt;
    for (int i = 0, sptr = n, tptr = n; i < q; i += B) {
        sort(queries + i, queries + min(q, i + B), [](tuple<ll, ll, ll, int> A, tuple<ll, ll, ll, int> B) {
            return get<1>(A) > get<1>(B);
        });
        for (int j = i; j < min(q, i + B); j++) {
            ll a, b, c, idx;
            tie(a, b, c, idx) = queries[j];
            while (sptr && by_s[sptr - 1].first >= a) {
                good_cnt[by_s[sptr - 1].second]++;
                if (good_cnt[by_s[sptr - 1].second] == 2) {
                    update(sum_ptr[by_s[sptr - 1].second], 1);
                }
                sptr--;
            }
            while (sptr != n && by_s[sptr].first < a) {
                good_cnt[by_s[sptr].second]--;
                if (good_cnt[by_s[sptr].second] == 1) {
                    update(sum_ptr[by_s[sptr].second], -1);
                }
                sptr++;
            }
            while (tptr && by_t[tptr - 1].first >= b) {
                good_cnt[by_t[tptr - 1].second]++;
                if (good_cnt[by_t[tptr - 1].second] == 2) {
                    update(sum_ptr[by_t[tptr - 1].second], 1);
                }
                tptr--;
            }
            while (tptr != n && by_t[tptr].first < b) {
                good_cnt[by_t[tptr].second]--;
                if (good_cnt[by_t[tptr].second] == 1) {
                    update(sum_ptr[by_t[tptr].second], -1);
                }
                tptr++;
            }
            ans[idx] = query(c, n);
        }
    }

    for (int i = 0; i < q; i++) cout << ans[i] << '\n';
    return 0;
}

• Subtask 1: 2 / 2
• Subtask 2: 0 / 20
• Subtask 3: 0 / 21
• Subtask 4: 0 / 57