Submission #312462

#	Time	Username	Problem	Language	Result	Execution time	Memory
312462		Trickster	원숭이와 사과 나무 (IZhO12_apple)	C++14	100 / 100	331 ms	4088 KiB

apple

#include <algorithm>
#include <string.h>
#include <iostream>
#include <stdio.h>
#include <vector>
#include <queue>
#include <cmath>
#include <set>
#include <map>

using namespace std;

#define lm (1<<30)
#define N 200010
#define ff first
#define ss second
#define ll long long
#define pb push_back
#define mod 1000000007
#define pii pair <ll, ll>
#define sz(a) int(a.size())
#pragma GCC target ("avx2")
#pragma GCC optimization ("O3")
#pragma GCC optimization ("unroll-loops")
ll bigmod(ll a,ll e) {if(e==0)return 1;ll x=bigmod(a*a%mod,e>>1);return e&1?x*a%mod:x;}

int T[N], L[N], R[N];
int nodes, q, c, tp, l, r;

int lft(int node)
{
    if(L[node] == -1) L[node] = ++nodes;
    return L[node];
}
int rgh(int node)
{
    if(R[node] == -1) R[node] = ++nodes;
    return R[node];
}

void upd(int a, int b, int l, int r, int node)
{
    if(l > b || r < a || T[node] == r-l+1) return;

    if(l >= a && r <= b) {
        T[node] = r-l+1;
        return;
    }

    upd(a, b, l, (l+r)/2, lft(node));
    upd(a, b, (l+r)/2+1, r, rgh(node));

    T[node] = T[L[node]] + T[R[node]];
}
int tap(int a, int b, int l, int r, int node)
{
    if(l > b || r < a || node == -1) return 0;

    if(l >= a && r <= b) return T[node];

    if(T[node] == r-l+1) return min(r, b) - max(l, a) + 1;

    return tap(a, b, l, (l+r)/2, L[node]) + tap(a, b, (l+r)/2+1, r, R[node]);
}

int main()
{
    for(int i = 0; i <= 100000; i++) L[i] = R[i] = -1;

    cin >> q;

    while(q--) {
        cin >> tp >> l >> r;

        l += c, r += c;

        if(tp == 1) c = tap(l, r, 1, lm, 0), cout << c << "\n";
        else upd(l, r, 1, lm, 0);
    }
}

Compilation message (stderr)

apple.cpp:23: warning: ignoring #pragma GCC optimization [-Wunknown-pragmas]
   23 | #pragma GCC optimization ("O3")
      | 
apple.cpp:24: warning: ignoring #pragma GCC optimization [-Wunknown-pragmas]
   24 | #pragma GCC optimization ("unroll-loops")
      |

• Subtask 1: 100 / 100