이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <iostream>
#include <vector>
#include <map>
#include <set>
#include <algorithm>
using namespace std;
vector<long long> trans(const vector<long long>& a, long long sub) {
vector<long long> na = a;
na.pop_back();
if (a.back() - sub > 1) {
long long val = (a.back() - sub) / 2;
if (na.size() == 0) na.push_back(val);
else na.back() += val;
}
return na;
}
map<pair<int, long long>, long long> f;
long long solve(long long x, vector<long long> a, int pos) {
if (a.size() == 0) return 1;
if (f.count({pos, a.back()})) return f[{pos, a.back()}];
long long ret = 0;
if (a.back() >= x) {
ret += solve(x, trans(a, x), pos + 1);
}
ret += solve(x, trans(a, 0), pos + 1);
return f[{pos, a.back()}] = ret;
}
vector<long long> arr;
long long solve2(long long x, long long last, int pos) {
if ((int) arr.size() <= pos && last < x) return 1;
if (f.count({pos, last})) return f[{pos, last}];
long long ret = 0;
if (last >= x) {
long long nlast = (pos + 1 < (int) arr.size() ? arr[pos + 1] : 0) + (last - x) / 2;
ret += solve2(x, nlast, pos + 1);
}
long long nlast = (pos + 1 < (int) arr.size() ? arr[pos + 1] : 0) + last / 2;
ret += solve2(x, nlast, pos + 1);
return f[{pos, last}] = ret;
}
vector<long long> sums;
long long solve3(long long x, int pos, long long sub) {
if (pos == -1) return sub == 0;
if (f.count({pos, sub})) return f[{pos, sub}];
long long cur = pos < (int) arr.size() ? arr[pos] : 0;
long long ret = 0;
if ((1LL << pos) <= (sums[pos] - sub) / x) {
long long what = solve3(x, pos - 1, max(0LL, sub + x * (1LL << pos) - (1LL << pos) * cur));
ret += what;
if (what == (1LL << pos)) {
ret += what;
return f[{pos, sub}] = ret;
}
}
ret += solve3(x, pos - 1, max(0LL, sub - (1LL << pos) * cur));
return f[{pos, sub}] = ret;
}
long long count_tastiness(long long x, vector<long long> a) {
f.clear(); sums.clear();
// for (int i = 0; i < (int) a.size(); ++i) {
// if (a[i] > x) {
// long long add = (a[i] - x) / 2;
// a[i] = x + ((a[i] - x) & 1);
// if (i + 1 == (int) a.size())
// a.push_back(add);
// else
// a[i + 1] += add;
// }
// }
long long s = 0, pw = 1;
for (int i = 0; i < 60; ++i) {
if (i < (int) a.size())
s += pw * a[i];
pw <<= 1;
sums.push_back(s);
}
// reverse(a.begin(), a.end());
arr = a;
// return solve2(x, arr[0], 0);
// cout << "2: " << solve2(x, arr[0], 0) << endl;
return solve3(x, 59, 0);
}
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