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Submission #304000

#TimeUsernameProblemLanguageResultExecution timeMemory
304000FdgPacking Biscuits (IOI20_biscuits)C++14
100 / 100
170 ms1016 KiB
#include <iostream> #include <vector> #include <map> #include <set> #include <algorithm> using namespace std; vector<long long> trans(const vector<long long>& a, long long sub) { vector<long long> na = a; na.pop_back(); if (a.back() - sub > 1) { long long val = (a.back() - sub) / 2; if (na.size() == 0) na.push_back(val); else na.back() += val; } return na; } map<pair<int, long long>, long long> f; long long solve(long long x, vector<long long> a, int pos) { if (a.size() == 0) return 1; if (f.count({pos, a.back()})) return f[{pos, a.back()}]; long long ret = 0; if (a.back() >= x) { ret += solve(x, trans(a, x), pos + 1); } ret += solve(x, trans(a, 0), pos + 1); return f[{pos, a.back()}] = ret; } vector<long long> arr; long long solve2(long long x, long long last, int pos) { if ((int) arr.size() <= pos && last < x) return 1; if (f.count({pos, last})) return f[{pos, last}]; long long ret = 0; if (last >= x) { long long nlast = (pos + 1 < (int) arr.size() ? arr[pos + 1] : 0) + (last - x) / 2; ret += solve2(x, nlast, pos + 1); } long long nlast = (pos + 1 < (int) arr.size() ? arr[pos + 1] : 0) + last / 2; ret += solve2(x, nlast, pos + 1); return f[{pos, last}] = ret; } vector<long long> sums; long long solve3(long long x, int pos, long long sub) { if (pos == -1) return sub == 0; if (f.count({pos, sub})) return f[{pos, sub}]; long long cur = pos < (int) arr.size() ? arr[pos] : 0; long long ret = 0; if ((1LL << pos) <= (sums[pos] - sub) / x) { long long what = solve3(x, pos - 1, max(0LL, sub + x * (1LL << pos) - (1LL << pos) * cur)); ret += what; if (what == (1LL << pos)) { ret += what; return f[{pos, sub}] = ret; } } ret += solve3(x, pos - 1, max(0LL, sub - (1LL << pos) * cur)); return f[{pos, sub}] = ret; } long long count_tastiness(long long x, vector<long long> a) { f.clear(); sums.clear(); // for (int i = 0; i < (int) a.size(); ++i) { // if (a[i] > x) { // long long add = (a[i] - x) / 2; // a[i] = x + ((a[i] - x) & 1); // if (i + 1 == (int) a.size()) // a.push_back(add); // else // a[i + 1] += add; // } // } long long s = 0, pw = 1; for (int i = 0; i < 60; ++i) { if (i < (int) a.size()) s += pw * a[i]; pw <<= 1; sums.push_back(s); } // reverse(a.begin(), a.end()); arr = a; // return solve2(x, arr[0], 0); // cout << "2: " << solve2(x, arr[0], 0) << endl; return solve3(x, 59, 0); }
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