# | 제출 시각 | 아이디 | 문제 | 언어 | 결과 | 실행 시간 | 메모리 |
---|---|---|---|---|---|---|---|
303595 | jtnydv25 | 버섯 세기 (IOI20_mushrooms) | C++17 | 849 ms | 624 KiB |
이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include "mushrooms.h"
#include <bits/stdc++.h>
using namespace std;
const int M = 8;
int val[200005];
struct node{
vector<int> states;
node* res[M];
vector<int> ask;
int maxQueries;
node(){
for(int i = 0; i < M; i++) res[i] = NULL;
maxQueries = 0;
}
void compute(){
int n = states.size();
if(n == 1) return;
maxQueries = 1;
int mn = 1 << 20;
for(int mask = 1; mask < (1 << M); mask++){
vector<int> perm;
for(int j = 0; j < M; j++) if(mask >> j & 1) perm.push_back(j);
if(((int)perm.size()) == 1) continue;
do{
vector<int> num(M);
for(int s : states){
int r = 0;
for(int j = 0; j + 1 < (int)perm.size(); j++) r += (s >> perm[j] & 1) != (s >> perm[j + 1] & 1);
num[r]++;
}
int V = *max_element(num.begin(), num.end());
if(V < mn){
mn = V;
ask = perm;
}
}while(next_permutation(perm.begin(), perm.end()));
}
vector<int> perm = ask;
vector<vector<int>> childStates(M);
for(int s : states){
int r = 0;
for(int j = 0; j + 1 < (int)perm.size(); j++) r += (s >> perm[j] & 1) != (s >> perm[j + 1] & 1);
childStates[r].push_back(s);
}
for(int i = 0; i < M; i++){
if(!childStates[i].empty()){
res[i] = new node();
res[i]->states = childStates[i];
res[i]->compute();
maxQueries = max(maxQueries, res[i]->maxQueries + 1);
}
}
}
void get(vector<int> positions){
if((int)states.size() == 1){
for(int i = 0; i < M; i++) val[positions[i]] = states[0] >> i & 1;
return;
}
vector<int> x;
for(int i : ask) x.push_back(positions[i]);
res[use_machine(x)]->get(positions);
}
};
int get(int pos){
return val[pos] = use_machine({0, pos});
}
struct decision_tree{
node * root;
decision_tree(){
root = new node();
for(int i = 0; i < (1 << M); i+=2) root->states.push_back(i);
root->compute();
}
void get(vector<int> positions){
root->get(positions);
}
};
const int K = 300;
int count_mushrooms(int N) {
decision_tree DT;
int n = min(N, K);
// int n = N;
// for(int j = 1; j < N; j++) get(j);
for(int i = 1; i < n; i += M - 1){
int st = i, en = i + M - 2;
if(en < n){
vector<int> positions = {0};
for(int j = st; j <= en; j++) positions.push_back(j);
DT.get(positions);
} else{
for(int j = st; j < n; j++) get(j);
}
}
int curr = n - accumulate(val, val + n, 0);
if(n == N) return curr;
vector<vector<int>> where(2);
for(int i = 0; i < n; i++) where[val[i]].push_back(i);
int id = (int)where[1].size() > (int) where[0].size();
int R = where[id].size() - 1;
for(int i = n; i < N; i += R){
int st = i, en = min(N - 1, i + R - 1);
vector<int> positions = {where[id][0]};
for(int j = 0; j <= en - st; j++){
positions.push_back(st + j);
positions.push_back(where[id][j + 1]);
}
int V = use_machine(positions);
assert(V % 2 == 0);
V /= 2;
if(id == 1) curr += V;
else curr += en - st + 1 - V;
}
return curr;
}
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