이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h> //Andrei Alexandru a.k.a Sho10
#define ll long long
#define double long double
#pragma GCC optimize("O3")
#pragma GCC optimize("Ofast")
#define all(a) (a).begin(), (a).end()
#define sz size
#define f first
#define s second
#define pb push_back
#define er erase
#define in insert
#define mp make_pair
#define pi pair
#define rc(s) return cout<<s,0
#define endl '\n'
#define mod 1000000007
#define PI 3.14159265359
#define MAXN 100005
#define INF 1000000005
#define LINF 1000000000000000005ll
#define CODE_START ios_base::sync_with_stdio(false);cin.tie(0);cout.tie(0);
using namespace std;
ll n,k,a[200005];
vector<ll>v;
int32_t main(){
CODE_START;
cin>>n>>k;
for(ll i=1;i<=n+k;i++)
{
cin>>a[i];
}
sort(a+1,a+n+k+1);
for(ll i=k+1;i>=1;i--)
{
for(ll j=n+k;j>=n+(i-1);j--)
{
ll l=i;
ll r=j;
ll s1=0,s2=0;
v.clear();
ll nr=k-i+1-(n+k-j);
while(l<r&&nr>=0){
if(a[l]+a[r]==a[i]+a[j]){
v.pb(a[l]);
v.pb(a[r]);
l++;
r--;
s2++;
}else if(a[l]+a[r]<a[i]+a[j]){
nr--;
l++;
}else if(a[l]+a[r]>a[i]+a[j]){
nr--;
r--;
}
if(s2>=n/2){
s1=1;
break;
}
}
if(s1==1){
sort(v.begin(),v.end());
for(auto it : v){
cout<<it<<' ';
}
return 0;
}
}
}
}
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