제출 #299904

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
299904		dsjong	Split the Attractions (IOI19_split)	C++14	0 / 100	120 ms	9268 KiB

split

#include "split.h"
#include <bits/stdc++.h>
#define pii pair<int, int>
using namespace std;
vector<int>adj[100005];
int par[100005], sum[100005], ans[100005];
pii A, B;
bool done=false;
int cnter, bad, n, head=-1;
void go(int x, int p, int v){
	if(cnter && !ans[x]){
		cnter--;
		ans[x]=v;
	}
	for(int y:adj[x]){
		if(y==p) continue;
		go(y, x, v);
	}
}
void dfs(int x, int p){
	par[x]=p;
	sum[x]=1;
	vector<pair<int, int>>cur;
	for(int y:adj[x]){
		if(y==p) continue;
		dfs(y, x);
		sum[x]+=sum[y];
		cur.push_back({sum[y], y});
	}
	cur.push_back({n-sum[x], p});
	if(done) return;
	for(auto [x, y]: cur){
		if(x>=A.first && n-x>=B.first){
			head=y;
			break;
		}
		if(x>=B.first && n-x>=A.first){
			head=y;
			swap(A, B);
			break;
		}
	}
	//A is baby
	if(head==-1) return;
	cnter=A.first;
	go(head, x, A.second);
	cnter=B.first;
	go(x, -1, B.second);
	for(int i=0;i<n;i++){
		if(!ans[i]) ans[i]=bad;
	}
	done=true;
}
vector<int> find_split(int _n, int a, int b, int c, vector<int> p, vector<int> q) {
	n=_n;
	assert((int) p.size()==n-1);
	for(int i=0;i<p.size();i++){
		int x=p[i], y=q[i];
		adj[x].push_back(y);
		adj[y].push_back(x);
	}
	vector<pii>v={{a, 1}, {b, 2}, {c, 3}};
	sort(v.begin(), v.end());
	A=v[0], B=v[1], bad=v[2].second;
	dfs(0, -1);
	vector<int>fans;
	for(int i=0;i<n;i++){
		fans.push_back(ans[i]);
	}
	return fans;
}

컴파일 시 표준 에러 (stderr) 메시지

split.cpp: In function 'void dfs(int, int)':
split.cpp:32:11: warning: structured bindings only available with '-std=c++17' or '-std=gnu++17'
   32 |  for(auto [x, y]: cur){
      |           ^
split.cpp: In function 'std::vector<int> find_split(int, int, int, int, std::vector<int>, std::vector<int>)':
split.cpp:57:15: warning: comparison of integer expressions of different signedness: 'int' and 'std::vector<int>::size_type' {aka 'long unsigned int'} [-Wsign-compare]
   57 |  for(int i=0;i<p.size();i++){
      |              ~^~~~~~~~~

• Subtask 1: 0 / 7
• Subtask 2: 0 / 11
• Subtask 3: 0 / 22
• Subtask 4: 0 / 24
• Subtask 5: 0 / 36