Submission #297213

#TimeUsernameProblemLanguageResultExecution timeMemory
297213miss_robotFriend (IOI14_friend)C++14
46 / 100
337 ms50032 KiB
#include <bits/stdc++.h> #include "friend.h" #pragma GCC optimize("O3") using namespace std; int st1(int n, int confidence[], int host[], int protocol[]){ vector<int> g(n); for(int i = 1; i < n; i++){ if(protocol[i]){ g[i] |= g[host[i]]; for(int j = 0; j < i; j++) if(g[host[i]]&(1<<j)) g[j] |= (1<<i); } if(protocol[i] != 1){ g[i] |= (1<<host[i]); g[host[i]] |= (1<<i); } } int t, s = 0; for(int i = 0; i < (1<<n); i++){ t = 0; for(int j = 0; j < n; j++) if(i&(1<<j)) t += confidence[j]; for(int j = 0; j < n; j++) if((i&(1<<j)) && (i&(g[j]))) t = 0; s = max(s, t); } return s; } int st2(int n, int confidence[]){ int s = 0; for(int i = 0; i < n; i++) s += confidence[i]; return s; } int st3(int n, int confidence[]){ int mx = 0; for(int i = 0; i < n; i++) mx = max(mx, confidence[i]); return mx; } void dfs(int u, vector< vector<int> >& g, vector<int>& dp, vector<int>& a){ for(int v : g[u]){ dfs(v, g, dp, a); a[u] += dp[v]; dp[u] += a[v]; } dp[u] = max(dp[u], a[u]); } int st4(int n, int confidence[], int host[]){ vector< vector<int> > g(n); vector<int> dp(n), a(n); for(int i = 1; i < n; i++) g[host[i]].push_back(i); for(int i = 0; i < n; i++) dp[i] = confidence[i]; dfs(0, g, dp, a); return dp[0]; } int bip(int u, vector< vector<int> >& g, vector<int>& vis, int c){ vis[u] = 1; int r = c; for(int v : g[u]) if(!vis[v]) r += c^1, bip(v, g, vis, c^1); return r; } int st5(int n, int host[], int protocol[]){ vector< vector<int> > g(n); for(int i = 1; i < n; i++){ if(protocol[i]){ for(int v : g[host[i]]) g[i].push_back(v), g[v].push_back(i); } else{ g[i].push_back(host[i]), g[host[i]].push_back(i); } } int s = 0; vector<int> vis(n); for(int i = 0; i < n; i++) if(!vis[i]){ vector<int> temp(n); s += max(bip(i, g, temp, 0), bip(i, g, vis, 1)); } return s; } int findSample(int n, int confidence[], int host[], int protocol[]){ if(n <= 10) return st1(n, confidence, host, protocol); for(int i = 2; i < n; i++) if(protocol[i] != protocol[i-1]) return st5(n, host, protocol); if(protocol[1] == 1) return st2(n, confidence); if(protocol[1]) return st3(n, confidence); return st4(n, confidence, host); }
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