| # | Time | Username | Problem | Language | Result | Execution time | Memory | 
|---|---|---|---|---|---|---|---|
| 293469 | Trickster | Highway Tolls (IOI18_highway) | C++14 | 0 ms | 0 KiB | 
This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <algorithm>
#include <highway.h>
#include <string.h>
#include <iostream>
#include <stdio.h>
#include <vector>
#include <queue>
#include <cmath>
#include <set>
#include <map>
using namespace std;
#define maxN 200010
#define ff first
#define ss second
#define ll long long
#define pb push_back
#define mod 1000000007
#define pii pair <ll, ll>
// #pragma GCC target ("avx2")
// #pragma GCC optimization ("O3")
// #pragma GCC optimization ("unroll-loops")
ll bigmod(ll a,ll e) {if(e==0)return 1;ll x=bigmod(a*a%mod,e>>1);return e&1?x*a%mod:x;}
int n, m;
int D[maxN];
int L[maxN];
vector <int> Lin, node;
vector <pii> Lv[maxN], E[maxN];
void dfs(int nd, int pr, int in)
{
    node.pb(nd);
    if(in != -1) {
        Lin.pb(in);
        L[nd] = L[pr]+1;
        Lv[L[nd]].pb({nd, in});
    }
    for(auto i: E[nd]) {
        if(i.ff == pr) continue;
        dfs(i.ff, nd, i.ss);
    }
}
void find_pair(int N, vector <int> U, vector <int> V, int A, int B) 
{
    m = U.size(), n = N;
    for(int i = 0; i < m; i++) {
        E[U[i]].pb({V[i], i});
        E[V[i]].pb({U[i], i});
        D[U[i]]++;
        D[V[i]]++;
    }
    int ok = 1;
    for(int i = 0; i < n; i++) {
        if(D[i] > 2) ok = 0;
    vector <int> arr;
    for(int i = 0; i < m; i++) arr.pb(0);
    int ans = ask(arr) / A;
    dfs(0, -1, -1);
    if(ok == 0) {
        int l = 0, r = Lv[ans].size()-1, md, S = 0, T;
        while(l <= r) {
            md = (l+r)/2;
    
            vector <int> arr;
            for(int h = 0; h < m; h++) arr.pb(0);
    
            for(int i = 0; i <= md; i++) arr[Lv[ans][i].ss] = 1;
    
            int cur = ask(arr);
    
            if(ans * A != cur) r = md-1, T = md;
            else l = md+1;
        }
    
        answer(S, Lv[ans][T].ff);
        return;
    }
    int l = 0, r = m-1, md, in = 0;
    while(l <= r) {
        md = (l+r)/2;
        vector <int> arr;
        for(int i = 0; i < m; i++) arr.pb(0);
        for(int i = 0; i <= md; i++) arr[Lin[i]] = 1;
        int cur = ask(arr);
        if(ans * A != cur) r = md-1, in = md;
        else l = md+1;
    }
    answer(node[in], U[ans+in]);
}
