#include<stdio.h>
int n,d[2097153],cnt[2097153],chk[2097153];
long long ans;
struct data
{
long long x,y;
}; data dy[2][2097153],cost[2][2097153];
void input()
{
int i;
scanf("%d",&n);
for(i=1; i<=n; i++) scanf("%d",&d[i]);
}
int maxval(int a,int b)
{
return a>b?a:b;
}
void process()
{
long long i,j,in;
dy[1][++cnt[1]].x=cost[1][1].x=d[1];
dy[1][cnt[1]].y=-1; cost[1][1].y=0;
for(i=2; i<=n; i++){
for(j=1; j<=cnt[i-1]; j++){
//x에 넣는경우
in = i%2;
if(chk[dy[1-in][j].x^d[i]] != i){
dy[in][++cnt[i]].x = dy[1-in][j].x^d[i];
dy[in][cnt[i]].y = dy[1-in][j].y;
cost[in][cnt[i]].y = cost[1-in][j].y;
cost[in][cnt[i]].x = cost[1-in][j].x + d[i];
chk[dy[1-in][j].x^d[i]]=i;
}
if(chk[dy[1-in][j].x] != i){
//y에 넣는경우
if(dy[1-in][j].y==-1) dy[in][++cnt[i]].y = d[i];
else dy[in][++cnt[i]].y = dy[1-in][j].y^d[i];
dy[in][cnt[i]].x = dy[1-in][j].x;
cost[in][cnt[i]].y = cost[1-in][j].y + d[i];
cost[in][cnt[i]].x = cost[1-in][j].x;
chk[dy[1-in][j].x] = i;
}
}
}
for(i=1; i<=cnt[n]; i++) if(dy[n%2][i].x==dy[n%2][i].y) ans=maxval(ans,maxval(cost[n%2][i].x,cost[n%2][i].y));
}
void output()
{
printf("%lld\n",ans);
}
int main()
{
input();
process();
output();
return 0;
}
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Memory limit exceeded |
0 ms |
131072 KB |
Memory limit exceeded |
2 |
Halted |
0 ms |
0 KB |
- |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Memory limit exceeded |
0 ms |
131072 KB |
Memory limit exceeded |
2 |
Halted |
0 ms |
0 KB |
- |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Memory limit exceeded |
0 ms |
131072 KB |
Memory limit exceeded |
2 |
Halted |
0 ms |
0 KB |
- |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Memory limit exceeded |
0 ms |
131072 KB |
Memory limit exceeded |
2 |
Halted |
0 ms |
0 KB |
- |