제출 #271735

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
271735		AKaan37	Restore Array (RMI19_restore)	C++17	0 / 100	20 ms	512 KiB

restore

//Bismillahirrahmanirrahim
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#include <bits/stdc++.h>

using namespace std;

typedef long long lo;
typedef pair< int,int > PII;
typedef pair< int,PII > PIII;
typedef pair< int,PIII > PIIII;
typedef pair< int,PIIII > PIIIII;

#define fi first
#define se second
#define mp make_pair
#define endl "\n"
#define pb push_back
#define fio() ios_base::sync_with_stdio(false);cin.tie(NULL);cout.tie(NULL)
#define FOR for(int i=0;i<n;i++)
#define mid ((start+end)/2)
#define ort ((bas+son)/2)

const lo inf = 1000000000000000000;
const lo KOK = 100000;
const lo LOG = 30;
const lo li = 500005;
const lo mod = 1000000007;

int n,m,b[li],a[li],k,flag,t;
int cev;
PIIIII p[li];
string s;
vector<int> v;

int main(void){
	scanf("%d %d",&n,&m);
	FOR a[i]=-1;
	for(int i=1;i<=m;i++){
		scanf("%d %d %d %d",&p[i].se.se.fi,&p[i].se.se.se.fi,&p[i].se.se.se.se,&p[i].fi);
		p[i].se.fi=p[i].se.se.se.fi-p[i].se.se.fi+1;
	}
	sort(p+1,p+n+1);
	int ind=-1;
	for(int i=1;i<=m;i++){
		if(p[i].fi==0)continue;
		if(ind==-1)ind=i-1;
		for(int j=p[i].se.se.fi;j<=p[i].se.se.se.fi;j++){
			a[j]=1;
		}
	}
	if(ind==-1)ind=m;
	for(int i=1;i<=ind;i++){
		int say=0;
		int tut=0;
		int boya=-1;
		for(int j=p[i].se.se.fi;j<=p[i].se.se.se.fi;j++){
			if(a[j]==1)say++;
			if(a[j]==-1)boya=j;
			tut++;
		}
		if(say==tut){printf("-1\n");return 0;}
		if(say==tut-1 && boya!=-1){
			a[boya]=0;
		}
	}
	FOR{
		if(a[i]==-1){printf("-1\n");return 0;}
	}
	FOR printf("%d ",a[i]);
	return 0;
}

컴파일 시 표준 에러 (stderr) 메시지

restore.cpp: In function 'int main()':
restore.cpp:39:7: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
   39 |  scanf("%d %d",&n,&m);
      |  ~~~~~^~~~~~~~~~~~~~~
restore.cpp:42:8: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
   42 |   scanf("%d %d %d %d",&p[i].se.se.fi,&p[i].se.se.se.fi,&p[i].se.se.se.se,&p[i].fi);
      |   ~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

• Subtask 1: 0 / 7
• Subtask 2: 0 / 13
• Subtask 3: 0 / 25
• Subtask 4: 0 / 55