제출 #268068

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
268068		ggooroo	Vision Program (IOI19_vision)	C++14	12 / 100	6 ms	3836 KiB

vision

#include "vision.h"
#include <cstdio>
#include <iostream>
#include <queue>
#include <set>
#include <map>
#define N 205
using namespace std;

int h, w, k, T, en, mn = 2e9, mx, v[N][N], zl1[40005], zr1[405], zr2[405], zl2[40005], o1[405], o2[405];
int dr[4] = {-1, 0, 0, 1}, dc[4] = {0, -1, 1, 0};
set<int> vi[40005];
vector<int> ans, l1[405], l2[405];
queue<int> qr, qc, qe;
int pq_num(int p, int q) {
	return p * w + q;
}

void pu(int p, int q, int e) {
	if (p < 0 || p >= h || q < 0 || q >= w || v[p][q] == T) return;
	v[p][q] = T;
	qr.push(p);
	qc.push(q);
	qe.push(e);
}

vector<int> in;

void construct_network(int hh, int ww, int kk) {
	int i, j, t1, t2, x1, x2;
	h = hh;
	w = ww;
	k = kk;
	for (i = 0; i < h; i++) {
		for (j = 0; j < w; j++) {
			l1[i + j].push_back(pq_num(i, j));
			l2[j - i + h - 1].push_back(pq_num(i, j));
		}
	}
	for (i = 0; i < h + w - 1; i++) {
		o1[i] = add_or(l1[i]);
		o2[i] = add_or(l2[i]);
		if (i > 0) zl1[i] = add_or({o1[i], zl1[i - 1]});
		else zl1[i] = o1[i];
		if (i > 0) zl2[i] = add_or({o2[i], zl2[i - 1]});
		else zl2[i] = o2[i];
	}
	for (i = h + w - 2; i >= 0; i--) {
		if (i + 1 < h + w - 2) zr1[i] = add_or({zr1[i + 1], o1[i]});
		else zr1[i] = o1[i];
		if (i + 1 < h + w - 2) zr2[i] = add_or({zr2[i + 1], o2[i]});
		else zr2[i] = o2[i];
	}
	ans.clear();
	for (i = 0; i < h; i++) {
		for (j = 0; j < w; j++) {
			t1 = i + j;
			t2 = j - i + h - 1;
			in.clear();
			k = kk;
			if (t1 - k >= 0) in.push_back(zl1[t1 - k]);
			if (t1 + k <= h + w - 2) in.push_back(zr1[t1 + k]);
			if (t2 - k >= 0) in.push_back(zl2[t2 - k]);
			if (t2 + k <= h + w - 2) in.push_back(zr2[t2 + k]);
			if (!in.empty()) x1 = add_or(in);
			else x1 = -1;
			if (x1 == -1) continue;
			in.clear();
			k = kk + 1;
			if (t1 - k >= 0) in.push_back(zl1[t1 - k]);
			if (t1 + k <= h + w - 2) in.push_back(zr1[t1 + k]);
			if (t2 - k >= 0) in.push_back(zl2[t2 - k]);
			if (t2 + k <= h + w - 2) in.push_back(zr2[t2 + k]);
			if (!in.empty()) x2 = add_or(in);
			else x2 = -1;
			if (x2 == -1) ans.push_back(add_and({x1, pq_num(i, j)}));
			else ans.push_back(add_and({add_xor({x1, x2}), pq_num(i, j), x1}));
		}
	}
	add_or(ans);
}

• Subtask 1: 0 / 10
• Subtask 2: 0 / 11
• Subtask 3: 0 / 11
• Subtask 4: 0 / 15
• Subtask 5: 12 / 12
• Subtask 6: 0 / 8
• Subtask 7: 0 / 14
• Subtask 8: 0 / 19