제출 #266487

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
266487		MarcoMeijer	Sure Bet (CEOI17_sure)	C++14	100 / 100	105 ms	5240 KiB

sure

#include <bits/stdc++.h>
using namespace std;

// macros
typedef long long ll;
typedef long double ld;
typedef pair<int, int> ii;
typedef pair<ll, ll> lll;
typedef tuple<int, int, int> iii;
typedef vector<int> vi;
typedef vector<ii> vii;
typedef vector<iii> viii;
typedef vector<ll> vll;
typedef vector<lll> vlll;
#define REP(a,b,c) for(int a=int(b); a<int(c); a++)
#define RE(a,c) REP(a,0,c)
#define RE1(a,c) REP(a,1,c+1)
#define REI(a,b,c) REP(a,b,c+1)
#define REV(a,b,c) for(int a=int(c-1); a>=int(b); a--)
#define FOR(a,b) for(auto& a : b)
#define all(a) a.begin(), a.end()
#define INF 1e9
#define EPS 1e-9
#define pb push_back
#define popb pop_back
#define fi first
#define se second
#define sz size()
mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());

// input
template<class T> void IN(T& x) {cin >> x;}
template<class H, class... T> void IN(H& h, T&... t) {IN(h); IN(t...); }

// output
template<class T1, class T2> void OUT(const pair<T1,T2>& x);
template<class T> void OUT(const T& x) {cout << x;}
template<class H, class... T> void OUT(const H& h, const T&... t) {OUT(h); OUT(t...); }
template<class T1, class T2> void OUT(const pair<T1,T2>& x) {OUT(x.fi,' ',x.se);}
template<class... T> void OUTL(const T&... t) {OUT(t..., "\n"); }
template<class H> void OUTLS(const H& h) {OUTL(h); }
template<class H, class... T> void OUTLS(const H& h, const T&... t) {OUT(h,' '); OUTLS(t...); }

//===================//
//  Added libraries  //
//===================//

//===================//
//end added libraries//
//===================//

void program();
int main() {
    ios_base::sync_with_stdio(false);
    cin.tie(NULL);
    cout.tie(NULL);
    program();
}


//===================//
//   begin program   //
//===================//

const int MX = 5e5;

int n;
double a[MX], b[MX];
double sma[MX], smb[MX];
double x;

void program() {
    IN(n);
    RE(i,n) IN(a[i], b[i]);
    sort(a,a+n,greater<double>());
    sort(b,b+n,greater<double>());
    sma[0] = a[0];
    smb[0] = b[0];
    REP(i,1,n) {
        sma[i] = sma[i-1]+a[i];
        smb[i] = smb[i-1]+b[i];
    }
    x = 0.0;
    RE(i,n) {
        int lb=0, ub=n-1;
        while(lb != ub) {
            int mid=(lb+ub)/2;
            double val = smb[mid];
            if(val >= sma[i]) ub = mid;
            else lb = mid+1;
        }
        x = max(x, min(sma[i], smb[lb])-double(i+lb+2));
        lb--;
        x = max(x, min(sma[i], smb[lb])-double(i+lb+2));
    }
    printf("%.4lf",(double)x);
}

• Subtask 1: 20 / 20
• Subtask 2: 40 / 40
• Subtask 3: 40 / 40