oj.uz

답안 #259927

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
259927 2020-08-08T19:54:34 Z thebes 치료 계획 (JOI20_treatment) C++14
5 / 100
 3000 ms 524292 KB 
#include <bits/stdc++.h>
using namespace std;

typedef long long ll;
typedef pair<ll,ll> pll;
typedef pair<int,int> pii;
#define F first
#define S second

const int MN = 1e5+5;
const ll inf = 1e12;
ll N, M, i, j, x, y, c, t, dis[MN], vs[MN], ans=1LL<<60;
struct idk{ll a,b,c,d;}arr[MN],go[MN];
map<ll,ll> mpx, mpy; vector<ll> ed;
struct pq{bool operator()(const pll&i,const pll&j){return i.S>j.S;}};
priority_queue<pll,vector<pll>,pq> q;

struct segtree{
    set<pii> st[6*MN]; ll n, c;
    void init(ll N){n=N;}
    void upd(ll i,ll s,ll e,ll ss,ll se,ll val,ll id){
        st[i].insert({val,id});
        if(s==e) return;
        else if((s+e)/2<ss) upd(2*i+1,(s+e)/2+1,e,ss,se,val,id);
        else if((s+e)/2>=se) upd(2*i,s,(s+e)/2,ss,se,val,id);
        else upd(2*i,s,(s+e)/2,ss,se,val,id), upd(2*i+1,(s+e)/2+1,e,ss,se,val,id);
    }
    inline void update(ll s,ll e,ll c,ll id){
        upd(1,1,n,s,e,c,id);
    }
    void qu(ll i,ll s,ll e,ll ss,ll se,ll a,ll b){
        if(s>=ss&&e<=se){
            auto it=st[i].lower_bound({a,0});
            while(it!=st[i].end()&&it->first<=b){
                if(!vs[it->second]){
                    vs[it->second]=1;
                    q.push({it->second,c+arr[it->second].c});
                }
                auto it2=it; it++;
                st[i].erase(it2);
            }
        }
        else if((s+e)/2<ss) qu(2*i+1,(s+e)/2+1,e,ss,se,a,b);
        else if((s+e)/2>=se) qu(2*i,s,(s+e)/2,ss,se,a,b);
        else qu(2*i,s,(s+e)/2,ss,se,a,b),qu(2*i+1,(s+e)/2+1,e,ss,se,a,b);
    }
    inline void query(ll s,ll e,ll x,ll y,ll cur){
        c = cur;
        qu(1,1,n,s,e,x,y);
    }
}stx, sty;

int main(){
    scanf("%lld%lld",&N,&M);
    for(i=1;i<=M;i++){
        scanf("%lld%lld%lld%lld",&t,&x,&y,&c);
        arr[i]={x,y,c,t};
        if(x==1) q.push({i,c}), x=-inf, vs[i]=1;
        if(y==N) ed.push_back(i), y=inf;
        y++;
        ll sx = t-y, ex = t-x;
        ll sy = t+x, ey = t+y;
        go[i]={sx,ex,sy,ey};
        mpx[sx]=mpx[ex]=mpy[sy]=mpy[ey]=0;
    }
    i=0; stx.init(mpx.size());
    for(auto it=mpx.begin();it!=mpx.end();it++)
        it->second = ++i;
    i=0; sty.init(mpy.size());
    for(auto it=mpy.begin();it!=mpy.end();it++)
        it->second = ++i;
    for(i=1;i<=M;i++){
        go[i].a=mpx[go[i].a]; go[i].b=mpx[go[i].b];
        go[i].c=mpy[go[i].c]; go[i].d=mpy[go[i].d];
        stx.update(go[i].a,go[i].b,go[i].c,i);
        stx.update(go[i].a,go[i].b,go[i].d,i);
        sty.update(go[i].c,go[i].d,go[i].a,i);
        sty.update(go[i].c,go[i].d,go[i].b,i);
    }
    memset(dis,-1,sizeof(dis));
    while(q.size()){
        pll x=q.top(); q.pop();
        dis[x.F]=x.S;
        int id = x.F;
        stx.query(go[id].a,go[id].b,go[id].c,go[id].d,x.S);
        sty.query(go[id].c,go[id].d,go[id].a,go[id].b,x.S);
    }
    for(auto v : ed){
        if(dis[v]!=-1) ans=min(ans,dis[v]);
    }
    printf("%lld\n",ans==1LL<<60?-1:ans);
    return 0;
}

Compilation message

treatment.cpp: In function 'int main()':
treatment.cpp:54:10: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
     scanf("%lld%lld",&N,&M);
     ~~~~~^~~~~~~~~~~~~~~~~~
treatment.cpp:56:14: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
         scanf("%lld%lld%lld%lld",&t,&x,&y,&c);
         ~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Subtask #1
0 / 4.0

# 결과 실행 시간 메모리 Grader output
1 Execution timed out 3100 ms 450184 KB Time limit exceeded
2 Halted 0 ms 0 KB -

Subtask #2
5.0 / 5.0

# 결과 실행 시간 메모리 Grader output
1 Correct 36 ms 57464 KB Output is correct
2 Correct 35 ms 57552 KB Output is correct
3 Correct 36 ms 57592 KB Output is correct
4 Correct 35 ms 57592 KB Output is correct
5 Correct 35 ms 57592 KB Output is correct
6 Correct 35 ms 57480 KB Output is correct
7 Correct 35 ms 57464 KB Output is correct
8 Correct 35 ms 57472 KB Output is correct
9 Correct 35 ms 57600 KB Output is correct
10 Correct 35 ms 57592 KB Output is correct
11 Correct 35 ms 57532 KB Output is correct
12 Correct 36 ms 57592 KB Output is correct
13 Correct 36 ms 57592 KB Output is correct
14 Correct 35 ms 57600 KB Output is correct
15 Correct 35 ms 57592 KB Output is correct
16 Correct 35 ms 57592 KB Output is correct
17 Correct 36 ms 57464 KB Output is correct
18 Correct 35 ms 57600 KB Output is correct
19 Correct 35 ms 57464 KB Output is correct

Subtask #3
0 / 30.0

# 결과 실행 시간 메모리 Grader output
1 Correct 36 ms 57464 KB Output is correct
2 Correct 35 ms 57552 KB Output is correct
3 Correct 36 ms 57592 KB Output is correct
4 Correct 35 ms 57592 KB Output is correct
5 Correct 35 ms 57592 KB Output is correct
6 Correct 35 ms 57480 KB Output is correct
7 Correct 35 ms 57464 KB Output is correct
8 Correct 35 ms 57472 KB Output is correct
9 Correct 35 ms 57600 KB Output is correct
10 Correct 35 ms 57592 KB Output is correct
11 Correct 35 ms 57532 KB Output is correct
12 Correct 36 ms 57592 KB Output is correct
13 Correct 36 ms 57592 KB Output is correct
14 Correct 35 ms 57600 KB Output is correct
15 Correct 35 ms 57592 KB Output is correct
16 Correct 35 ms 57592 KB Output is correct
17 Correct 36 ms 57464 KB Output is correct
18 Correct 35 ms 57600 KB Output is correct
19 Correct 35 ms 57464 KB Output is correct
20 Runtime error 1059 ms 524292 KB Execution killed with signal 9 (could be triggered by violating memory limits)
21 Halted 0 ms 0 KB -

Subtask #4
0 / 61.0

# 결과 실행 시간 메모리 Grader output
1 Execution timed out 3100 ms 450184 KB Time limit exceeded
2 Halted 0 ms 0 KB -