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답안 #255167

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
255167 2020-07-31T13:16:56 Z amoo_safar parentrises (BOI18_parentrises) C++14
100 / 100
 59 ms 14352 KB 
// Zende bad Shoma nasime faghat !
#include <bits/stdc++.h>

#define pb push_back
#define F first
#define S second
#define all(x) x.begin(), x.end()
#define debug(x) cerr << #x << " : " << x << '\n'

using namespace std;

typedef long long ll;
typedef long double ld;
typedef string str;
typedef pair<ll, ll> pll;

const ll Mod = 1000000007LL;
const int N = 3e2 + 10;
const ll Inf = 2242545357980376863LL;
const ll Log = 30;

str Solve1(){
	vector<int> O, C;
	int sm = 0;
	str s;
	cin >> s;
	int n = s.size();
	vector<int> mk(n, 0);

	for(int i = 0; i < n; i++){
		if(s[i] == '('){
			O.pb(i);
			sm ++;
		} else {
			C.pb(i);
			sm --;
		}
	}
	reverse(all(C));

	str Im = "impossible";
	int Ao = (sm <= 0 ? -sm: 0);
	int Ac = (sm >= 0 ? sm: 0);

	int idx = -1;
	for(int i = 0; i < n; i++){
		if(Ao + i > (int)O.size()) break;
		if(Ac + i > (int)C.size()) break;
		int po = (Ao + i == 0 ? -1 : O[Ao + i - 1]);
		int pc = (Ac + i == 0 ? n : C[Ac + i - 1]);
		if(po >= pc) break;
		idx = i;
	}
	//debug(idx);
	if(idx == -1) return Im;
	for(int i = 0; i < Ao + idx; i++) mk[O[i]] = 1;
	for(int i = 0; i < Ac + idx; i++) mk[C[i]] = 1;

	str res = "";
	int Sr = 0, Sb = 0;
	for(int i = 0; i < n; i++){
		if(mk[i]){
			res += "G";
			if(s[i] == '('){
				Sr ++;
				Sb ++;
			} else {
				Sr --;
				Sb --;
			}
		} else {
			if(s[i] == '('){
				if(Sr < Sb) Sr ++, res += "R";
				else Sb ++, res += "B";
			} else {
				if(Sr > Sb) Sr --, res += "R";
				else Sb --, res += "B";
			}
		}
		if(min(Sr, Sb) < 0) return Im;
	}

	assert(Sr == 0); assert(Sb == 0);
	return res;
}

ll dp[N][N][3];

ll ans[N];

int main(){
	ios::sync_with_stdio(0); cin.tie(0); cout.tie(0);
	dp[1][2][0] = 1;
	dp[1][1][1] = 1;
	
	for(int i = 1; i + 1 < N; i++){
		for(int sm = 0; sm < N; sm ++){
			dp[i][sm][0] %= Mod;
			dp[i][sm][1] %= Mod;
			dp[i][sm][2] %= Mod;

			if(dp[i][sm][0]){
				if(sm + 1 < N) dp[i + 1][sm + 1][1] += dp[i][sm][0];
				if(sm + 2 < N) dp[i + 1][sm + 2][0] += dp[i][sm][0];
				
				if(sm >= 1) dp[i + 1][sm - 1][0] += dp[i][sm][0];
				if(sm >= 2) dp[i + 1][sm - 2][2] += dp[i][sm][0];
			}
			
			if(dp[i][sm][1]){
				
				if(sm + 1 < N) dp[i + 1][sm + 1][1] += dp[i][sm][1];
				//dp[i + 1][sm + 2][0] += dp[i][sm][0];
				
				//if(sm >= 1) dp[i + 1][sm - 1][0] += dp[i][sm][0];
				if(sm >= 2) dp[i + 1][sm - 2][2] += dp[i][sm][1];
			}
			
			if(dp[i][sm][2]){
				if(sm + 1 < N) dp[i + 1][sm + 1][2] += dp[i][sm][2];
				//dp[i + 1][sm + 2][0] += dp[i][sm][2];
				
				//if(sm >= 1) dp[i + 1][sm - 1][0] += dp[i][sm][2];
				if(sm >= 2) dp[i + 1][sm - 2][2] += dp[i][sm][2];
			}
		}
		
		ans[i] = (dp[i][0][0] + dp[i][0][1] + dp[i][0][2]) % Mod;
	}


	int PR;
	cin >> PR;
	int T;
	cin >> T;
	while(T --){
		if(PR == 1) cout << Solve1() << '\n';
		else {
			int m;
			cin >> m;
			cout << ans[m] << '\n';
		}
	}
	return 0;
}

Subtask #1
5.0 / 5.0

# 결과 실행 시간 메모리 Grader output
1 Correct 2 ms 2560 KB Output is correct
2 Correct 2 ms 2560 KB Output is correct
3 Correct 2 ms 2560 KB Output is correct
4 Correct 2 ms 2560 KB Output is correct
5 Correct 2 ms 2560 KB Output is correct

Subtask #2
11.0 / 11.0

# 결과 실행 시간 메모리 Grader output
1 Correct 2 ms 2560 KB Output is correct
2 Correct 2 ms 2560 KB Output is correct
3 Correct 2 ms 2560 KB Output is correct
4 Correct 2 ms 2560 KB Output is correct
5 Correct 2 ms 2560 KB Output is correct

Subtask #3
6.0 / 6.0

# 결과 실행 시간 메모리 Grader output
1 Correct 2 ms 2560 KB Output is correct
2 Correct 2 ms 2560 KB Output is correct
3 Correct 2 ms 2560 KB Output is correct
4 Correct 2 ms 2560 KB Output is correct
5 Correct 2 ms 2560 KB Output is correct
6 Correct 2 ms 2560 KB Output is correct
7 Correct 2 ms 2560 KB Output is correct
8 Correct 2 ms 2560 KB Output is correct
9 Correct 3 ms 2560 KB Output is correct
10 Correct 3 ms 2560 KB Output is correct

Subtask #4
28.0 / 28.0

# 결과 실행 시간 메모리 Grader output
1 Correct 2 ms 2560 KB Output is correct
2 Correct 2 ms 2560 KB Output is correct
3 Correct 2 ms 2560 KB Output is correct
4 Correct 2 ms 2560 KB Output is correct
5 Correct 2 ms 2560 KB Output is correct
6 Correct 2 ms 2560 KB Output is correct
7 Correct 2 ms 2560 KB Output is correct
8 Correct 2 ms 2560 KB Output is correct
9 Correct 3 ms 2560 KB Output is correct
10 Correct 3 ms 2560 KB Output is correct
11 Correct 3 ms 2688 KB Output is correct
12 Correct 3 ms 2688 KB Output is correct
13 Correct 2 ms 2560 KB Output is correct
14 Correct 3 ms 2688 KB Output is correct
15 Correct 2 ms 2688 KB Output is correct
16 Correct 8 ms 2688 KB Output is correct
17 Correct 5 ms 3712 KB Output is correct
18 Correct 4 ms 2844 KB Output is correct
19 Correct 5 ms 3328 KB Output is correct
20 Correct 5 ms 3776 KB Output is correct
21 Correct 59 ms 3320 KB Output is correct
22 Correct 35 ms 14336 KB Output is correct
23 Correct 25 ms 4532 KB Output is correct
24 Correct 36 ms 8500 KB Output is correct
25 Correct 43 ms 14352 KB Output is correct

Subtask #5
6.0 / 6.0

# 결과 실행 시간 메모리 Grader output
1 Correct 2 ms 2560 KB Output is correct

Subtask #6
16.0 / 16.0

# 결과 실행 시간 메모리 Grader output
1 Correct 2 ms 2560 KB Output is correct
2 Correct 2 ms 2560 KB Output is correct

Subtask #7
28.0 / 28.0

# 결과 실행 시간 메모리 Grader output
1 Correct 2 ms 2560 KB Output is correct
2 Correct 2 ms 2560 KB Output is correct
3 Correct 3 ms 2560 KB Output is correct