Submission #253582

#TimeUsernameProblemLanguageResultExecution timeMemory
253582HynDufSplit the Attractions (IOI19_split)C++14
0 / 100
140 ms17272 KiB
#include "split.h" #include <bits/stdc++.h> #define task "SPLIT" #define all(v) (v).begin(), (v).end() #define rep(i, l, r) for (int i = (l); i <= (r); ++i) #define Rep(i, r, l) for (int i = (r); i >= (l); --i) #define DB(X) { cerr << #X << " = " << (X) << '\n'; } #define DB1(A, _) { cerr << #A << "[" << _ << "] = " << (A[_]) << '\n'; } #define DB2(A, _, __) { cerr << #A << "[" << _ << "][" << __ << "] = " << (A[_][__]) << '\n'; } #define DB3(A, _, __, ___) { cerr << #A << "[" << _ << "][" << __ << "][" << ___ << "] = " << (A[_][__][___]) << '\n'; } #define PR(A, l, r) { cerr << '\n'; rep(_, l, r) DB1(A, _); cerr << '\n';} #define SZ(x) ((int)(x).size()) #define pb push_back #define eb emplace_back #define pf push_front #define F first #define S second #define by(x) [](const auto& a, const auto& b) { return a.x < b.x; } // sort(arr, arr + N, by(a)); #define next ___next #define prev ___prev #define y1 ___y1 #define left ___left #define right ___right #define y0 ___y0 #define div ___div #define j0 ___j0 #define jn ___jn using ll = long long; using ld = long double; using ull = unsigned long long; using namespace std; typedef pair<int, int> ii; typedef pair<ii, int> iii; typedef vector<int> vi; typedef vector<ii> vii; typedef vector<ll> vl; const int N = 2e5 + 3; //int n, m, a, b, c; int sz[N], eul[N], st[N], ed[N], neu, dep[N], par[N], id[4]; vi g[N], leaf[4]; ii A[4]; bool vis[N]; int team[N]; void dfs(int u) { st[u] = ++neu; eul[neu] = u; vis[u] = 1; sz[u] = 1; for (int v : g[u]) if (!vis[v]) { dep[v] = dep[u] + 1; dfs(v); sz[u] += sz[v]; } ed[u] = neu; } void getleaves(int u, int teamid) { vis[u] = 1; sz[u] = 1; for (int v : g[u]) if (!vis[v] && team[v] == teamid) { par[v] = u; getleaves(v, teamid); sz[u] += sz[v]; } if (sz[u] == 1) leaf[teamid].eb(u); } void setteam(int teamid, int lim, int siz) { int redun = siz - lim; rep(i, 1, redun) { if (leaf[teamid].empty()) break; int cur = leaf[teamid].back(); team[cur] = 3; leaf[teamid].pop_back(); if (--sz[par[cur]] == 1) leaf[teamid].eb(par[cur]); } } bool canreach(int u, int mxd) { rep(i, st[u], ed[u]) for (int v : g[eul[i]]) if (dep[v] < mxd) return 1; return 0; } vi find_split(int n, int a, int b, int c, vi p, vi q) { vi ans(n, 0); //ios_base::sync_with_stdio(false); cin.tie(nullptr); //cin >> n >> m >> a >> b >> c; int m = SZ(p); rep(i, 1, m) { //int u, v; //cin >> u >> v; //u++, v++; int u = p[i - 1] + 1, v = q[i - 1] + 1; g[u].eb(v); g[v].eb(u); } A[0] = {a, 1}; A[1] = {b, 2}; A[2] = {c, 3}; sort(A, A + 3); a = A[0].F; b = A[1].F; c = A[2].F; rep(i, 1, 3) id[i] = A[i - 1].S; dfs(1); int u = 0, mxd = -1; rep(i, 1, n) if (sz[i] >= a && mxd < dep[i]) { mxd = dep[i]; u = i; } if (n - sz[u] >= a) { int rA = u, rB = 1; if (sz[u] >= b) { rB = u; rA = 1; rep(i, st[u], ed[u]) team[eul[i]] = 2; // B-team rep(i, 1, n) if (team[i] == 0) team[i] = 1; // A-team } else { rep(i, st[u], ed[u]) team[eul[i]] = 1; // A-team rep(i, 1, n) if (team[i] == 0) team[i] = 2; // B-team } fill(vis, vis + 1 + n, 0); getleaves(rA, 1); getleaves(rB, 2); setteam(1, a, sz[rA]); setteam(2, b, sz[rB]); rep(i, 1, n) ans[i - 1] = id[team[i]]; } else { int sz1 = sz[u]; int sz2 = n - sz[u]; rep(i, st[u], ed[u]) team[eul[i]] = 1; // A-team rep(i, 1, n) if (team[i] == 0) team[i] = 2; // B-team bool ok = 0; for (int v : g[u]) if (dep[v] > dep[u]) { if (canreach(v, dep[u])) { rep(i, st[v], ed[v]) team[eul[i]] = 2; sz2 += sz[v]; sz1 -= sz[v]; if (sz2 >= a) { ok = 1; break; } } } if (!ok) { rep(i, 1, n) ans[i - 1] = 0; return ans; } int rA = u, rB = 1; if (sz1 >= sz2) { swap(rA, rB); swap(sz1, sz2); rep(i, 1, n) if (team[i] == 1) team[i] = 2; else team[i] = 1; } fill(vis, vis + 1 + n, 0); getleaves(rA, 1); getleaves(rB, 2); setteam(1, a, sz1); setteam(2, b, sz2); rep(i, 1, n) ans[i - 1] = id[team[i]]; } return ans; } /* int main() { freopen("SPLIT.in", "r", stdin); int n, m, a, b, c; cin >> n >> m >> a >> b >> c; vi pp(m, 0), qq(m, 0); rep(i, 0, m - 1) cin >> pp[i] >> qq[i]; vi res = find_split(n, a, b, c, pp, qq); for (int v : res) cout << v << ' '; return 0; } */
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