/*input
6
3 2
5 3
4 1
2 1
4 3
3 2
*/
#include <bits/stdc++.h>
using namespace std;
namespace my_template {
typedef long long ll;
typedef long double ld;
typedef complex<ld> cd;
typedef pair<int, int> pi;
typedef pair<ll, ll> pl;
typedef pair<ld, ld> pd;
typedef vector<int> vi;
typedef vector<vi> vii;
typedef vector<ld> vd;
typedef vector<ll> vl;
typedef vector<vl> vll;
typedef vector<pi> vpi;
typedef vector<vpi> vpii;
typedef vector<pl> vpl;
typedef vector<cd> vcd;
typedef vector<pd> vpd;
typedef vector<bool> vb;
typedef vector<vb> vbb;
typedef std::string str;
typedef std::vector<str> vs;
#define x first
#define y second
#define debug(...) cout<<"["<<#__VA_ARGS__<<": "<<__VA_ARGS__<<"]\n"
const ld PI = 3.14159265358979323846264338327950288419716939937510582097494L;
template<typename T>
pair<T, T> operator+(const pair<T, T> &a, const pair<T, T> &b) { return pair<T, T>(a.x + b.x, a.y + b.y); }
template<typename T>
pair<T, T> operator-(const pair<T, T> &a, const pair<T, T> &b) { return pair<T, T>(a.x - b.x, a.y - b.y); }
template<typename T>
T operator*(const pair<T, T> &a, const pair<T, T> &b) { return (a.x * b.x + a.y * b.y); }
template<typename T>
T operator^(const pair<T, T> &a, const pair<T, T> &b) { return (a.x * b.y - a.y * b.x); }
template<typename T>
void print(vector<T> vec, string name = "") {
cout << name;
for (auto u : vec)
cout << u << ' ';
cout << '\n';
}
}
using namespace my_template;
const int MOD = 1000000007;
const ll INF = std::numeric_limits<ll>::max();
const int MX = 100101;
ll add(ll a) {
return a * (a - 1) / 2;
}
int main() {
ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0);
int N;
cin >> N;
vl kiek(MX, 0);
vl pab(MX, 0);
ll ats = 0;
ll viso = 0;
ll liko = 0;
ll st = 0;
for (int i = 0; i < N; ++i)
{
ll h, k;
cin >> h >> k;
viso += k;
kiek[h]++;
pab[h - k]++;
st = max(st, h);
}
for (ll i = st; i >= 1; --i)
{
kiek[i] += kiek[i + 1];
{
ll stumsiu = min(pab[i], liko);
liko -= stumsiu;
pab[i - 1] += stumsiu;
pab[i] -= stumsiu;
}
kiek[i] -= pab[i];
ll desiu = min(kiek[i], viso / i);
// printf("i = %d, kiek = %lld, desiu = %lld\n", i, kiek[i], desiu);
// liko = kiek[i] - desiu;
liko += kiek[i] - desiu;
ats += add(desiu);
viso -= desiu;
// if (desiu < kiek[i]) {
// ll did = viso % i;
// ll maz = i - did;
// ats += maz * add(desiu);
// desiu++;
// ats += did * add(desiu);
// break;
// } else {
// }
}
printf("%lld\n", ats);
}
/* Look for:
* special cases (n=1?)
* overflow (ll vs int?)
* the exact constraints (multiple sets are too slow for n=10^6 :( )
* array bounds
*/
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Correct |
1 ms |
1920 KB |
Output is correct |
2 |
Correct |
1 ms |
1920 KB |
Output is correct |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Correct |
1 ms |
1920 KB |
Output is correct |
2 |
Correct |
2 ms |
1920 KB |
Output is correct |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Correct |
1 ms |
1920 KB |
Output is correct |
2 |
Correct |
1 ms |
1920 KB |
Output is correct |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Correct |
1 ms |
1920 KB |
Output is correct |
2 |
Correct |
1 ms |
1920 KB |
Output is correct |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Correct |
2 ms |
1920 KB |
Output is correct |
2 |
Correct |
2 ms |
1920 KB |
Output is correct |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Correct |
5 ms |
2048 KB |
Output is correct |
2 |
Correct |
6 ms |
2048 KB |
Output is correct |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Correct |
8 ms |
2048 KB |
Output is correct |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Incorrect |
12 ms |
2048 KB |
Output isn't correct |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Correct |
18 ms |
2048 KB |
Output is correct |
2 |
Correct |
21 ms |
2048 KB |
Output is correct |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Correct |
23 ms |
2048 KB |
Output is correct |
2 |
Correct |
19 ms |
2048 KB |
Output is correct |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Incorrect |
27 ms |
2048 KB |
Output isn't correct |
2 |
Halted |
0 ms |
0 KB |
- |