#include <bits/stdc++.h>
#define m first
#define c second;
using namespace std;
typedef pair<long long,long long> line;
const long long inf = 102345678901234567;
long long get(line L, int x){ return L.m * x + L.c; }
long long H[100005];
int C[100005];
struct lichao{
int s, e, m;
lichao *l, *r;
line val = line(0,inf);
lichao(int S, int E){
s = S, e = E, m = (s+e)/2;
if(s == e-1) return;
l = new lichao(s, m);
r = new lichao(m, e);
}
void insert(line L){
if(get(L, m) < get(val, m)) swap(L, val); ///make val the dominant one
if(s == e-1) return;
if(get(L, s) < get(val, s)) l->insert(L); ///L has some chance in l
else r->insert(L); ///L has some chance in r
}
long long query(int x){
if(s == e-1) return get(val, x);
else if(x >= m) return min(get(val,x), r->query(x));
else return min(get(val,x), l->query(x));
}
} *root;
signed main(){
ios_base::sync_with_stdio(false);
long long ans = 0;
int n; cin >> n;
for(int i = 0;i < n;i++) cin >> H[i];
for(int i = 0;i < n;i++){
cin >> C[i];
ans += C[i];
C[i] *= -1;
}
root = new lichao(-2000001, 0);
int dp = C[0];
root->insert(line(-2*H[0], dp + H[0]*H[0]));
for(int i = 1;i < n;i++){
dp = root->query(H[i]);
dp += H[i]*H[i] + C[i];
root->insert(line(-2*H[i], dp + H[i]*H[i]));
}
cout << dp + ans << "\n";
}
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Runtime error |
115 ms |
131076 KB |
Execution killed with signal 9 (could be triggered by violating memory limits) |
2 |
Halted |
0 ms |
0 KB |
- |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Runtime error |
121 ms |
131072 KB |
Execution killed with signal 9 (could be triggered by violating memory limits) |
2 |
Halted |
0 ms |
0 KB |
- |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Runtime error |
115 ms |
131076 KB |
Execution killed with signal 9 (could be triggered by violating memory limits) |
2 |
Halted |
0 ms |
0 KB |
- |