제출 #248853

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
248853		egekabas	Bubble Sort 2 (JOI18_bubblesort2)	C++14	22 / 100	155 ms	99104 KiB

bubblesort2

#include <bits/stdc++.h>
#define ff first
#define ss second
#define pb push_back
#define mp make_pair
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
typedef long double ld;
typedef pair<ll, ll> pll;
typedef pair<ull, ull> pull;
typedef pair<int, int> pii;
typedef pair<ld, ld> pld;
int seg[8000009];
int lazy[8000009];
void push(int v){
    lazy[2*v] += lazy[v];
    lazy[2*v+1] += lazy[v];
    seg[2*v] += lazy[v];
    seg[2*v+1] += lazy[v];
    lazy[v] = 0;
}
void upd(int v, int tl, int tr, int l, int r, int val){
    if(r < tl || tr < l) return;
    if(l <= tl && tr <= r){
        seg[v] += val;
        lazy[v] += val;
    }
    else{
        push(v);
        upd(2*v, tl, (tl+tr)/2, l, r, val);
        upd(2*v+1, (tl+tr)/2+1, tr, l, r, val);
        seg[v] = max(seg[2*v], seg[2*v+1]);
    }
}
vector<int> mpp;
int get(int x){
    return lower_bound(mpp.begin(), mpp.end(), x)-mpp.begin();
}
set<int, greater<int>> s[2000009];
int n, N;
vector<int> a, x, v;

void erase(int idx){
    if(*s[a[idx]].begin() == idx+1){
        upd(1, 0, N, a[idx], a[idx], -(idx+1));
        s[a[idx]].erase(idx+1);
        if(s[a[idx]].size())
            upd(1, 0, N, a[idx], a[idx], *s[a[idx]].begin());
    }
    else
        s[a[idx]].erase(idx+1);
    upd(1, 0, N, a[idx], N, 1);
}
void add(int idx){
    if(s[a[idx]].empty()){
        upd(1, 0, N, a[idx], a[idx], (idx+1));        
    }
    else if(idx+1 > *s[a[idx]].begin()){
        upd(1, 0, N, a[idx], a[idx], -*s[a[idx]].begin());
        upd(1, 0, N, a[idx], a[idx], (idx+1));    
    }
    s[a[idx]].insert(idx+1);
    upd(1, 0, N, a[idx], N, -1);
}
vector<int> countScans(vector<int> a1, vector<int> a2, vector<int> a3){
    a = a1;
    x = a2;
    v = a3;
    n = a.size();
    for(auto u : a)
        mpp.pb(u);
    for(auto u : v)
        mpp.pb(u);
    sort(mpp.begin(), mpp.end());
    mpp.resize(unique(mpp.begin(), mpp.end())-mpp.begin());
    N = mpp.size()-1;

    for(int i = 0; i < n; ++i){
        a[i] = get(a[i]);
    }
    for(int i = 0; i < int(v.size()); ++i)
        v[i] = get(v[i]);

    
    for(int i = 0; i < n; ++i){
        s[a[i]].insert(i+1);
        upd(1, 0, N, a[i], n, -1);
    }
    for(int i = 0; i < n; ++i)
        if(*s[a[i]].begin() == i+1){
            upd(1, 0, N, a[i], a[i], i+1);
        }
    vector<int> ans(x.size());
    for(int i = 0; i < int(x.size()); ++i){
        erase(x[i]);
        a[x[i]] = v[i];
        add(x[i]);
        ans[i] = max(seg[1], 0);
    }
    return ans;
}

• Subtask 1: 0 / 17
• Subtask 2: 0 / 21
• Subtask 3: 22 / 22
• Subtask 4: 0 / 40