제출 #246908

#제출 시각아이디문제언어결과실행 시간메모리
246908receed공장들 (JOI14_factories)C++14
100 / 100
5297 ms139644 KiB
#include "factories.h" #include <iostream> #include <iomanip> #include <cstdio> #include <vector> #include <algorithm> #include <cmath> #include <cstring> #include <cassert> #include <string> #include <set> #include <map> #include <random> #include <bitset> #include <string> #include <unordered_set> #include <unordered_map> #include <deque> #include <queue> #define rep(i, n) for (int i = 0; i < (n); i++) #define all(x) (x).begin(), (x).end() #define rall(x) (x).rbegin(), (x).rend() using namespace std; using ll = long long; using ul = unsigned long long; using ld = long double; const int N = 500001, L = 19; vector<pair<ll, ll>> g[N]; int tin[N], tout[N], ct, up[L][N], th[N], par[N], st[N], li[N * 2]; ll h[N], d1[N], d2[N], inf = 1e16; void dfs(int v, int p) { up[0][v] = p; tin[v] = ++ct; for (auto &u : g[v]) if (u.first != p) { h[u.first] = h[v] + u.second; th[u.first] = th[v] + 1; dfs(u.first, v); } tout[v] = ++ct; } int isp(int u, int v) { return tin[u] <= tin[v] && tout[v] <= tout[u]; } int lca(int u, int v) { if (isp(u, v)) return u; for (int i = L - 1; i >= 0; i--) if (!isp(up[i][u], v)) u = up[i][u]; return up[0][u]; } void Init(int n, int a[], int b[], int d[]) { rep(i, n - 1) { g[a[i]].push_back({b[i], d[i]}); g[b[i]].push_back({a[i], d[i]}); } dfs(0, 0); rep(i, L - 1) rep(j, n) up[i + 1][j] = up[i][up[i][j]]; rep(i, n) d1[i] = d2[i] = inf; } long long Query(int s, int x[], int t, int y[]) { int lp = 0; rep(i, s) { li[lp++] = x[i]; d1[x[i]] = 0; } rep(i, t) { li[lp++] = y[i]; d2[y[i]] = 0; } sort(li, li + lp, [](int v1, int v2) {return tin[v1] < tin[v2];}); int k = lp; rep(i, k - 1) li[lp++] = lca(li[i], li[i + 1]); sort(li, li + lp, [](int v1, int v2) {return tin[v1] < tin[v2];}); lp = unique(li, li + lp) - li; int sp = 0; rep(j, lp) { int i = li[j]; if (sp == 0) st[sp++] = i; else { while (tout[st[sp - 1]] < tout[i]) sp--; par[i] = st[sp - 1]; st[sp++] = i; } } ll ans = inf; for (int i = lp - 1; i > 0; i--) { ll v = li[i], cd = h[v] - h[par[v]]; d1[v] += cd; d2[v] += cd; ans = min(ans, min(d1[v] + d2[par[v]], d2[v] + d1[par[v]])); d1[par[v]] = min(d1[par[v]], d1[v]); d2[par[v]] = min(d2[par[v]], d2[v]); } rep(i, lp) d1[li[i]] = d2[li[i]] = inf; return ans; }
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