이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#include <robots.h>
using namespace std;
using ll = long long;
#define pb push_back
#define dbg(x) cerr << #x << " " << x << "\n"
const int NA = 5e4, NT = 1e6;
int a, b, t;
int x[1 + NA], y[1 + NA];
pair <int, int> toy[1 + NT];
bool used[1 + NT];
int orderSmall[1 + NT], orderWeak[1 + NT];
bool check (int bound) {
for (int i = 1; i <= t; i++)
used[i] = false;
priority_queue <pair <int, int>> pq;
int j = 1;
for (int i = 1; i <= a; i++) {
while (j <= t && x[i] > toy[orderWeak[j]].first) {
pq.push ({toy[orderWeak[j]].second, orderWeak[j]});
j++;
}
int lft = bound;
while (lft && pq.size ()) {
used[pq.top ().second] = true;
pq.pop ();
lft--;
}
}
queue <int> q;
j = 1;
for (int i = 1; i <= b; i++) {
while (j <= t && y[i] > toy[orderSmall[j]].second) {
if (not used[orderSmall[j]])
q.push (orderSmall[j]);
j++;
}
int lft = bound;
while (lft && q.size ()) {
used[q.front ()] = true;
q.pop ();
lft--;
}
}
for (int i = 1; i <= t; i++)
if (not used[i])
return false;
return true;
}
inline bool cmpWeak (int a, int b) {
return toy[a].first < toy[b].first;
}
inline bool cmpSmall (int a, int b) {
return toy[a].second < toy[b].second;
}
int putaway (int A, int B, int T, int X[], int Y[], int W[], int S[]) {
a = A; b = B; t = T;
for (int i = 1; i <= a; i++)
x[i] = X[i - 1];
for (int i = 1; i <= b; i++)
y[i] = Y[i - 1];
for (int i = 1; i <= t; i++)
toy[i] = {W[i - 1], S[i - 1]};
sort (x + 1, x + a + 1);
sort (y + 1, y + b + 1);
for (int i = 1; i <= t; i++)
orderWeak[i] = i, orderSmall[i] = i;
sort (orderWeak + 1, orderWeak + t + 1, cmpWeak);
sort (orderSmall + 1, orderSmall + t + 1, cmpSmall);
int lb = 1, rb = t, ans = -1;
while (lb <= rb) {
int mid = (lb + rb) / 2;
if (check (mid))
ans = mid, rb = mid - 1;
else
lb = mid + 1;
}
return ans;
}
/**
int X[1 + NA], Y[1 + NA];
int W[1 + NT], S[1 + NT];
int main () {
ios::sync_with_stdio (false);
cin.tie (0); cout.tie (0);
int A, B, T;
cin >> A >> B >> T;
for (int i = 0; i < A; i++)
cin >> X[i];
for (int i = 0; i < B; i++)
cin >> Y[i];
for (int i = 0; i < T; i++)
cin >> W[i] >> S[i];
cout << putaway (A, B, T, X, Y, W, S) << "\n";
return 0;
}
**/
/**
3 2 10
6 2 9
4 7
4 6
8 5
2 3
7 9
1 8
5 1
3 3
8 7
7 6
10 5
**/
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