제출 #240985

#제출 시각아이디문제언어결과실행 시간메모리
240985aggu_01000101Growing Vegetable is Fun 3 (JOI19_ho_t3)C++14
60 / 100
509 ms766664 KiB
#include <iostream> #include <cmath> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> #define INF 100000000 //#define int long long #define lchild(i) (i*2 + 1) #define rchild(i) (i*2 + 2) #define mid(l, u) ((l+u)/2) #define x(p) p.first #define y(p) p.second #define MOD 998244353 #define ordered_set tree<pair<int, int>, null_type,less<pair<int, int>>, rb_tree_tag,tree_order_statistics_node_update> using namespace std; int n; const int N = 405; int dp[N][N][N][3]; int g[3][N]; int cc[] = {0, 0, 0}; int cmp[N][3]; signed main(){ ios_base::sync_with_stdio(false); cin.tie(NULL); g[0][0] = g[1][0] = g[2][0] = INF; cin>>n; char c; for(int i = 1;i<=n;i++){ cmp[i][0] = cc[0]; cmp[i][1] = cc[1]; cmp[i][2] = cc[2]; cin>>c; if(c=='R') g[0][cc[0]++] = i; else if(c=='G') g[1][cc[1]++] = i; else g[2][cc[2]++] = i; } if(n==1){ cout<<0<<endl; return 0; } for(int i = 0;i<=n;i++) for(int j = 0;j<=n;j++) for(int k = 0;k<=n;k++) for(int x = 0;x<3;x++) dp[i][j][k][x] = INF; for(int i = n-1;i>=1;i--){ for(int aused = n;aused>=0;aused--){ for(int bused = n;bused >= 0 ;bused--){ int cused = i - (aused + bused); int ause = INF, buse = INF, cuse = INF; if(aused>cc[0] || bused>cc[1] || cused>cc[2]) continue; if(cused<0) continue; int currind; //calculate use[0] if(cc[0] > aused) { currind = g[0][aused] + max((int) 0, bused - cmp[g[0][aused]][1]) + max((int) 0, cused - cmp[g[0][aused]][2]); ause = (currind - (i + 1)) + ((i == (n - 1)) ? 0 : dp[i + 1][aused + 1][bused][0]); } //calculate buse if(cc[1] > bused) { currind = g[1][bused] + max((int) 0, aused - cmp[g[1][bused]][0]) + max((int) 0, cused - cmp[g[1][bused]][2]); buse = (currind - (i + 1)) + ((i == (n - 1)) ? 0 : dp[i + 1][aused][bused + 1][1]); } //calculate cuse if(cc[2] > cused) { currind = g[2][cused] + max((int) 0, aused - cmp[g[2][cused]][0]) + max((int) 0, bused - cmp[g[2][cused]][1]); cuse = (currind - (i + 1)) + ((i == (n - 1)) ? 0 : dp[i + 1][aused][bused][2]); } dp[i][aused][bused][0] = min(buse, cuse); dp[i][aused][bused][1] = min(ause, cuse); dp[i][aused][bused][2] = min(buse, ause); } } } int ans = INF; ans = min(ans, (g[0][0] - 1) + dp[1][1][0][0]); ans = min(ans, (g[1][0] - 1) + dp[1][0][1][1]); ans = min(ans, (g[2][0] - 1) + dp[1][0][0][2]); if(ans>=INF) ans = -1; cout<<ans<<"\n"; } //2^(2k - 1) - 2^(k-1) /* 4 4 RGWR GRRG WGGW WWWR 5 5 RGRGW GRRGW WGGWR RWRGW RGWGW 20 YYGYYYGGGGRGYYGRGRYG */
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