This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <iostream>
#include <vector>
#include <algorithm>
#include <cmath>
#include <cassert>
using namespace std;
using ll = long long;
#define MIN(a, b) (((a) < (b)) ? (a) : (b))
#define MAX(a, b) (((a) < (b)) ? (b) : (a))
int const nmax = 200;
int const inf = 1000000000 + 5;
int v[5 + nmax], t[5 + nmax];
int dp[5 + 2 * nmax][5 + 2 * nmax][5 + nmax][2];
int n;
int extract(int x, int y, int val, int h){
  if(val < 0)
    return inf;
  else
    return dp[x][y][val][h];
}
int dist(int x, int y){
  return fabs(v[x] - v[y]);
}
void update(int &number, int val){
  number = min(number, val);
}
int main()
{
  int l;
  cin >> n >> l;
  for(int i = 1;i <= n; i++)
    cin >> v[i];
  for(int i = 1;i <= n; i++)
    cin >> t[i];
  for(int i = 1;i <= n; i++) {
    v[n + i] = v[i] + l;
    t[n + i] = t[i];
  }
  for(int i = 0;i <= nmax * 2; i++)
    for(int j = 0; j <= nmax * 2; j++)
      for(int h = 0; h <= nmax; h++)
        dp[i][j][h][0] = dp[i][j][h][1] = inf;
  dp[n][n][(abs(l - v[n]) <= t[n])][0] = fabs(l - v[n]);
  dp[n + 1][n + 1][(abs(l - v[n + 1]) <= t[n + 1])][0] = fabs(l - v[n + 1]);
  int result = 0;
  for(int dif = 0; dif < n; dif++)
    for(int i = 1;i <= 2 * n; i++){
      int j = i + dif;
      if(j <= 2 * n){
        for(int k = 0; k <= dif + 1; k++){
          int time = dp[i][j][k][0] + dist(i - 1, i);
          update(dp[i - 1][j][k + (time <= t[i - 1])][0], time);
          time = dp[i][j][k][1] + dist(i - 1, j);
          update(dp[i - 1][j][k + (time <= t[i - 1])][0], time);
          time = dp[i][j][k][0] + dist(j + 1, i);
          update(dp[i][j + 1][k + (time <= t[j + 1])][1], time);
          time = dp[i][j][k][1] + dist(j + 1, j);
          update(dp[i][j + 1][k + (time <= t[j + 1])][1], time);
          if(dp[i][j][k][0] <= inf - 5 || dp[i][j][k][1] <= inf - 5)
            result = max(result, k);
        }
      }
    }
  cout << result;
  return 0;
}
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