이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#include <ext/rope>
using namespace std;
using namespace __gnu_pbds;
using namespace __gnu_cxx;
#define ll long long
#define ii pair<ll,ll>
#define iii pair<ii,ll>
#define endl '\n'
#define debug(x) cout << #x << " is " << x << endl;
#define rep(x,start,end) for(auto x=start-(start>end);x!=end-(start>end);x+=(start<end?1:-1))
#define all(x) x.begin(),x.end()
ll MAX(ll a){return a;}
ll MIN(ll a){return a;}
template<typename... Args>
ll MAX(ll a, Args... args) { return max(a,MAX(args...)); }
template<typename... Args>
ll MIN(ll a, Args... args) { return min(a,MIN(args...)); }
#define indexed_set tree<ll, null_type, less<ll>,rb_tree_tag,tree_order_statistics_node_update>
const ll INF=1e18;
int n,l;
ll pos[205];
ll t[205];
ll memo[2][205][205][205];
ll dp(int par,int l,int r,int taken){
if (memo[par][l][r][taken]!=-1) return memo[par][l][r][taken];
ll res=INF;
//try dont take anything
if (par==0 && l!=0){
res=MIN(res,dp(0,l-1,r,taken)+pos[l]-pos[l-1],dp(1,l-1,r,taken)+pos[l]+(pos[n+1]-pos[r]));
}
else if (par==1 && r!=n+1){
res=MIN(res,dp(1,l,r+1,taken)+pos[r+1]-pos[r],dp(0,l,r+1,taken)+(pos[n+1]-pos[r])+pos[l]);
}
//now try increase taken by 1
ll tim;
if (taken){
if (par==0 && l!=0){
tim=dp(0,l-1,r,taken-1)+pos[l]-pos[l-1];
if (tim<=t[l]) res=min(res,tim);
tim=dp(1,l-1,r,taken-1)+pos[l]+(pos[n+1]-pos[r]);
if (tim<=t[l]) res=min(res,tim);
}
else if (par==1 && r!=n+1){
tim=dp(1,l,r+1,taken-1)+pos[r+1]-pos[r];
if (tim<=t[r]) res=min(res,tim);
tim=dp(0,l,r+1,taken-1)+(pos[n+1]-pos[r])+pos[l];
if (tim<=t[r]) res=min(res,tim);
}
}
//cout<<par<<" "<<l<<" "<<r<<" "<<taken<<" "<<res<<endl;
return memo[par][l][r][taken]=res;
}
int main(){
ios::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
cin>>n>>l;
pos[0]=0,pos[n+1]=l;
rep(x,1,n+1) cin>>pos[x];
rep(x,1,n+1) cin>>t[x];
memset(memo,-1,sizeof(memo));
memo[0][0][n+1][0]=0;
memo[1][0][n+1][0]=0;
int ans=0;
rep(x,0,n+1)
rep(y,0,n+1)
if (dp(0,x,x+1,y)<INF || dp(1,x,x+1,y)<INF) ans=max(ans,y);
cout<<ans<<endl;
}
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