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답안 #213052

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
213052 2020-03-24T19:51:25 Z arman_ferdous 이상한 기계 (APIO19_strange_device) C++17
0 / 100
 5 ms 512 KB 
/* at time = 0, (x, y) = (0, 0)
 * we need to find minimum t > 0, such that (x, y) = 0 again ie. the cycle period.
 * now, y = 0 = t % B => t = K * B (for some integer K)
 * putting t in x's eqn and simplifying gives us a nice formula
 * K * (B + 1) % A = 0
 * from here it is easy to find K's value. 
 * answering queries are just merging intervals
 */

#include <bits/stdc++.h>
using namespace std;

using ll = long long;
const double oo = 1e19;

vector<pair<ll,ll>> interval;

int main () {
  int n;
  ll A, B;
  scanf("%d %lld %lld", &n, &A, &B);

  int inf = 0; ll sum = 0;
  ll g = __gcd(A, B + 1);
  ll K = A / g;
  ll T = K * B;
  
  if(K * 1.0 > oo / B * 1.0) inf = 1;
  while(n--) {
    ll l, r;
    scanf("%lld %lld", &l, &r);

    if(r - l + 1 >= T) {
      assert(1==2);
      printf("%lld\n", T);
      return 0;
    } sum += r - l + 1;

    ll le = l % T;
    ll ri = r % T;
    if(le <= ri) {
      interval.push_back({le, ri});

    }
    else {
      interval.push_back({0, ri});
      interval.push_back({le, T - 1});
    }
  }

  if(inf) printf("%lld\n", sum);
  else {
    ll ans = 0, ptr = -1;
    sort(interval.begin(), interval.end());
    for(int i = 0; i < (int)interval.size(); i++) {
      if(ptr < interval[i].first) {
        ans += interval[i].second - interval[i].first + 1;
        ptr = interval[i].second;
      }
      else {
        ans += max(0ll, interval[i].second - ptr);
        ptr = max(ptr, interval[i].second);
      }
    }
    printf("%lld\n", ans);
  }
  return 0;
}

Compilation message

strange_device.cpp: In function 'int main()':
strange_device.cpp:21:8: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
   scanf("%d %lld %lld", &n, &A, &B);
   ~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~
strange_device.cpp:31:10: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
     scanf("%lld %lld", &l, &r);
     ~~~~~^~~~~~~~~~~~~~~~~~~~~

Subtask #1
0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Runtime error 5 ms 384 KB Execution killed with signal 11 (could be triggered by violating memory limits)
2 Halted 0 ms 0 KB -

Subtask #2
0 / 5.0

# 결과 실행 시간 메모리 Grader output
1 Runtime error 5 ms 512 KB Execution killed with signal 11 (could be triggered by violating memory limits)
2 Halted 0 ms 0 KB -

Subtask #3
0 / 5.0

# 결과 실행 시간 메모리 Grader output
1 Runtime error 5 ms 512 KB Execution killed with signal 11 (could be triggered by violating memory limits)
2 Halted 0 ms 0 KB -

Subtask #4
0 / 5.0

# 결과 실행 시간 메모리 Grader output
1 Runtime error 5 ms 512 KB Execution killed with signal 11 (could be triggered by violating memory limits)
2 Halted 0 ms 0 KB -

Subtask #5
0 / 5.0

# 결과 실행 시간 메모리 Grader output
1 Runtime error 5 ms 512 KB Execution killed with signal 11 (could be triggered by violating memory limits)
2 Halted 0 ms 0 KB -

Subtask #6
0 / 20.0

# 결과 실행 시간 메모리 Grader output
1 Runtime error 5 ms 512 KB Execution killed with signal 11 (could be triggered by violating memory limits)
2 Halted 0 ms 0 KB -

Subtask #7
0 / 20.0

# 결과 실행 시간 메모리 Grader output
1 Runtime error 5 ms 512 KB Execution killed with signal 11 (could be triggered by violating memory limits)
2 Halted 0 ms 0 KB -

Subtask #8
0 / 30.0

# 결과 실행 시간 메모리 Grader output
1 Runtime error 5 ms 384 KB Execution killed with signal 11 (could be triggered by violating memory limits)
2 Halted 0 ms 0 KB -