이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include "bits/stdc++.h"
using namespace std;
#define FAST ios_base::sync_with_stdio(false); cin.tie(0);
#define pb push_back
#define eb emplace_back
#define ins insert
#define ph push
#define f first
#define s second
#define cbr cerr << "hi\n"
#define mmst(x, v) memset((x), v, sizeof ((x)))
#define siz(x) ll(x.size())
#define all(x) (x).begin(), (x).end()
#define lbd(x, y) lower_bound(all(x), y)
#define ubd(x, y) upper_bound(all(x), y)
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count()); //can be used by calling rng() or shuffle(A, A+n, rng)
inline long long rand(long long x, long long y) { return (rng() % (y+1-x)) + x; } //inclusivesss
string inline to_string(char c) {string s(1,c);return s;} template<typename T> inline T gcd(T a,T b){ return a==0?llabs(b):gcd(b%a,a); }
typedef long long ll;
typedef long double ld;
#define FOR(i,s,e) for(ll i=s;i<=ll(e);++i)
#define DEC(i,s,e) for(ll i=s;i>=ll(e);--i)
typedef pair<ll,ll>pi; typedef pair<ll,pi>spi; typedef pair<pi,pi>dpi;
#define LLINF ((long long) 1e18)//1234567890987654321
#define INF 1234567890ll
// #define cerr if(0)cout
#define MAXN (100006)
ll n, c, r, A[MAXN];
multiset<pi> ms; // no partial intersection, only full intersection
struct node {
int s,e,m;
ll v;
node *l,*r;
node(int S,int E) {
s=S,e=E,m=(s+e)>>1;
if(s^e) {
l=new node(s,m);
r=new node(m+1,e);
v=max(l->v,r->v);
} else v=A[s];
}
ll rmq(int x,int y){
if(x>y) return -LLINF;
if(s==x&&e==y) return v;
if(x>m) return r->rmq(x,y);
else if(y<=m) return l->rmq(x,y);
else return max(l->rmq(x,m),r->rmq(m+1,y));
}
} *seg;
struct fen {
ll fw[MAXN];
void update(int x,int y,ll nval) {
++ x, ++ y;
assert(x>0&&y+1>0);
pupdate(x,nval);
pupdate(y+1,-nval);
}
void pupdate(int x,ll nval) {
for(;x<MAXN;x+=x&(-x)) fw[x]+=nval;
}
ll sum(ll x) { // point sum
++ x; ll res=0;
assert(x>0);
for(;x;x-=x&(-x)) res+=fw[x];
return res;
}
} fen;
int GetBestPosition(int N, int C, int R, int *K, int *S, int *E) {
n=N, c=C, r=R;
FOR(i,0,n-2)A[i]=K[i];
seg=new node(0,n-2);
FOR(i,0,C-1) {
auto [s,e] = tie(S[i],E[i]);
while(ms.size()) {
int no=0;
auto b4=ms.lower_bound(pi(s,0));
if(b4 != ms.begin() && (--b4)->s >= s) { // intersect with front
ll val=b4->s-s;
s=b4->f-val;
ms.erase(b4);
} else ++ no;
auto aft=ms.lower_bound(pi(s,0));
if(aft != ms.end() && aft->f <= e) { // intersect with back
ll val=e-aft->f;
e=aft->s+val;
ms.erase(aft);
} else ++ no;
if(no==2) break;
}
ms.ins(pi(s,e));
tie(S[i],E[i])=tie(s,e);
}
return 0;
// assert(S[C-1]==0&&E[C-1]==n-1);
FOR(i,0,C-1) {
assert(E[i]-1<=n-2);
if(seg->rmq(S[i], E[i]-1) < r) {
fen.update(S[i], E[i], 1);
}
}
ll mx=-LLINF, pos=-1;
FOR(i,0,n-1) {
if(fen.sum(i) > mx) mx=fen.sum(i), pos=i;
}
return int(pos);
}
컴파일 시 표준 에러 (stderr) 메시지
tournament.cpp: In function 'int GetBestPosition(int, int, int, int*, int*, int*)':
tournament.cpp:76:8: warning: decomposition declaration only available with -std=c++1z or -std=gnu++1z
auto [s,e] = tie(S[i],E[i]);
^
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