이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include "walk.h"
#include <algorithm>
#include <queue>
#include <set>
#include <map>
#include <tuple>
#define fs first
#define se second
using namespace std;
typedef long long llong;
typedef pair<int, int> pii;
typedef pair<llong, llong> pll;
const llong inf = 1e18;
int n, m;
int X[100001], H[100001];
int L[100001], R[100001], Y[100001];
llong dijkstra(int s, int e, const vector<vector<pii>> &edge) {
int n = int(edge.size()) - 1;
vector<llong> D(n + 1, inf);
priority_queue<pll> pq;
D[s] = 0;
pq.emplace(0, s);
while (!pq.empty()) {
llong x, d;
tie(d, x) = pq.top();
pq.pop();
d = -d;
if (D[x] != d) continue;
for (pii i : edge[x]) {
llong nd = d + i.se;
if (nd < D[i.fs]) {
D[i.fs] = nd;
pq.emplace(-nd, i.fs);
}
}
}
return D[e] < inf ? D[e] : -1;
}
llong solve(int st, int ed) {
vector<vector<int>> P(n + 1), S(n + 1), E(n + 1), M(20, vector<int>(n + 1));
for (int i = 1; i <= n; ++i) {
M[0][i] = H[i];
}
for (int i = 1; i < 20; ++i) {
for (int j = 1; j <= n; ++j) {
M[i][j] = M[i - 1][j];
int k = j + (1 << i - 1);
if (k <= n) M[i][j] = max(M[i][j], M[i - 1][k]);
}
}
P[st].push_back(0);
P[ed].push_back(0);
S[st].push_back(0);
S[ed].push_back(0);
E[st].push_back(0);
E[ed].push_back(0);
for (int i = 1; i <= m; ++i) {
P[L[i]].push_back(Y[i]);
P[R[i]].push_back(Y[i]);
S[L[i]].push_back(Y[i]);
E[R[i]].push_back(Y[i]);
if (L[i] < st && st < R[i]) {
int prv = st, nxt = st;
for (int b = 20; b--; ) {
if (M[b][nxt] < Y[i]) nxt += (1 << b);
if ((1 << b) < prv && M[b][prv - (1 << b) + 1] < Y[i]) prv -= (1 << b);
}
P[prv].push_back(Y[i]);
P[nxt].push_back(Y[i]);
}
if (L[i] < ed && ed < R[i]) {
int prv = ed, nxt = ed;
for (int b = 20; b--; ) {
if (M[b][nxt] < Y[i]) nxt += (1 << b);
if ((1 << b) < prv && M[b][prv - (1 << b) + 1] < Y[i]) prv -= (1 << b);
}
P[prv].push_back(Y[i]);
P[nxt].push_back(Y[i]);
}
}
map<int, vector<pii>> I;
vector<vector<pii>> edge(1);
auto add_edge = [&](int a, int b, int c) {
edge[a].emplace_back(b, c);
edge[b].emplace_back(a, c);
};
multiset<int> sp;
int idx = 0;
for (int i = 1; i <= n; ++i) {
for (int j : S[i]) sp.insert(j);
sort(P[i].begin(), P[i].end());
P[i].erase(unique(P[i].begin(), P[i].end()), P[i].end());
vector<pii> V;
for (int j : P[i]) {
auto itL = sp.lower_bound(j);
auto itU = sp.upper_bound(j);
if (itL != sp.begin()) {
int x = *prev(itL);
V.emplace_back(j, x);
}
if (itU != sp.end() && *itU <= H[i]) {
int x = *itU;
V.emplace_back(j, x);
}
}
vector<int> N;
for (pii j : V) {
N.push_back(j.fs);
N.push_back(j.se);
}
sort(N.begin(), N.end());
N.erase(unique(N.begin(), N.end()), N.end());
edge.resize(edge.size() + N.size());
for (pii j : V) {
int a = upper_bound(N.begin(), N.end(), j.fs) - N.begin() + idx;
int b = upper_bound(N.begin(), N.end(), j.se) - N.begin() + idx;
add_edge(a, b, abs(j.fs - j.se));
}
for (int j : N) I[j].emplace_back(i, ++idx);
for (int j : E[i]) sp.erase(sp.find(j));
}
for (int i = 1; i <= m; ++i) {
const vector<pii> &V = I[Y[i]];
auto it = lower_bound(V.begin(), V.end(), pii(L[i], 0));
int pri = -1, prx;
while (it != V.end() && it->fs <= R[i]) {
if (pri != -1) add_edge(pri, it->se, X[it->fs] - prx);
prx = X[it->fs];
pri = it->se;
++it;
}
}
const vector<pii> &V = I[0];
if (int(V.size()) < 2) return -1;
st = V[0].se, ed = V.back().se;
return dijkstra(st, ed, edge);
}
llong min_distance(vector<int> x, vector<int> h, vector<int> l, vector<int> r, vector<int> y, int s, int g) {
n = x.size();
if (s == g) return 0;
m = l.size();
for (int i = 1; i <= n; ++i) {
X[i] = x[i - 1];
H[i] = h[i - 1];
}
for (int i = 1; i <= m; ++i) {
L[i] = l[i - 1] + 1;
R[i] = r[i - 1] + 1;
Y[i] = y[i - 1];
}
return solve(s + 1, g + 1);
}
컴파일 시 표준 에러 (stderr) 메시지
walk.cpp: In function 'llong solve(int, int)':
walk.cpp:51:33: warning: suggest parentheses around '-' inside '<<' [-Wparentheses]
int k = j + (1 << i - 1);
~~^~~
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