답안 #172312

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
172312 2020-01-01T06:46:25 Z qkxwsm Simurgh (IOI17_simurgh) C++14
컴파일 오류
0 ms 0 KB
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include "simurgh.h"

using namespace std;
using namespace __gnu_pbds;

template<class T, class U>
void ckmin(T &a, U b)
{
    if (a > b) a = b;
}

template<class T, class U>
void ckmax(T &a, U b)
{
    if (a < b) a = b;
}

struct custom_hash
{
    template<class T>
    T operator()(T a) const
    {
        return (a ^ (a >> 15)) ^ (a * 69);
    }
};

template<class T, class U>
using hash_table = gp_hash_table<T, U, custom_hash>;

#define MP make_pair
#define PB push_back
#define LB lower_bound
#define UB upper_bound
#define fi first
#define se second
#define SZ(x) ((int) (x).size())
#define ALL(x) (x).begin(), (x).end()
#define FOR(i, a, b) for (auto i = (a); i < (b); i++)
#define FORD(i, a, b) for (auto i = (a) - 1; i >= (b); i--)
#define MAXN 513

typedef long long ll;
typedef long double ld;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
typedef vector<int> vi;
typedef vector<ll> vl;
typedef vector<pii> vpi;
typedef vector<pll> vpl;

int N, M, T;
int eid[MAXN][MAXN];
int st[MAXN], ft[MAXN];
hash_table<int, int> rec[MAXN];
vi edge[MAXN];
bitset<MAXN> seen;
int parent[MAXN], depth[MAXN];
int ans[MAXN * MAXN];
vi quer;
vi ret;

int get(int a, int b)
{
    if (rec[a].find(b) != rec[a].end()) return rec[a][b];
    quer.clear();
    if (a == 0 && b == 0)
    {
        FOR(i, 1, N)
        {
            quer.PB(eid[i][parent[i]]);
        }
        rec[a][b] = count_common_roads(quer);
    }
    else
    {
        FOR(i, 1, N)
        {
            if (i == a) continue;
            quer.PB(eid[i][parent[i]]);
        }
        quer.PB(b);
        rec[a][b] = count_common_roads(quer);
    }
    return rec[a][b];
    //take the tree, except delete a and add edge b.
}

void dfs(int u, int p)
{
    st[u] = T; ft[u] = T;
    T++;
    seen[u] = true;
    for (int v : edge[u])
    {
        if (v == p) continue;
        if (seen[v])
        {
            ckmin(ft[u], st[v]);
            continue;
        }
        parent[v] = u;
        depth[v] = depth[u] + 1;
        dfs(v, u);
        ckmin(ft[u], ft[v]);
    }
}

vi find_roads(int n, vi e1, vi e2)
{
    N = n; M = SZ(e1);
    FOR(i, 0, M)
    {
        edge[e1[i]].PB(e2[i]);
        edge[e2[i]].PB(e1[i]);
        eid[e1[i]][e2[i]] = i;
        eid[e2[i]][e1[i]] = i;
        ans[i] = -1;
    }
    if (Q != 30000)
    {
        FOR(i, 0, M) ans[i] = 0;
        int R = -1;
        FOR(i, 0, N)
        {
            quer.clear();
            FOR(j, 0, N)
            {
                if (i == j) continue;
                quer.PB(eid[i][j]);
            }
            depth[i] = count_common_roads(quer);
            // cerr << depth[i] << ' ';
        }
        // cerr << endl;
        FOR(i, 0, N)
        {
            if (depth[i] == 1)
            {
                R = i;
                break;
            }
        }
        //R is a leaf.
        //for each of the N edges connected to R, check to see if it's the on one.
        FOR(i, 0, N)
        {
            if (i == R) continue;
            quer.clear();
            int s = 0;
            while(s == R || s == i) s++;
            FOR(j, 0, N)
            {
                if (j == s || j == R || j == i) continue;
                quer.PB(eid[s][j]);
            }
            quer.PB(eid[R][s]);
            quer.PB(eid[R][i]);
            // cerr << "sz " << SZ(quer) << endl;
            int si = count_common_roads(quer);
            quer.pop_back();
            quer.PB(eid[s][i]);
            int ri = count_common_roads(quer);
            quer.pop_back();
            quer.pop_back();
            quer.PB(eid[s][i]);
            quer.PB(eid[R][i]);
            int rs = count_common_roads(quer);
            if (ri < rs || ri < si)
            {
                T = i;
                break;
            }
            //is R...i on?
        }
        ans[eid[R][T]] = 1;
        FOR(i, 0, N)
        {
            if (i == R) continue;
            int lo = -1, hi;
            vi idk;
            FOR(j, 0, N)
            {
                if (i == j || j == R) continue;
                idk.PB(j);
            }
            FOR(j, 0, depth[i])
            {
                lo++; hi = SZ(idk) - 1;
                while(hi > lo)
                {
                    int mid = (hi + lo) >> 1;
                    quer.clear();
                    FOR(k, 0, mid + 1)
                    {
                        quer.PB(eid[idk[k]][i]);
                    }
                    FOR(k, mid + 1, SZ(idk))
                    {
                        quer.PB(eid[idk[k]][R]);
                    }
                    quer.PB(eid[R][i]);
                    int x = count_common_roads(quer);
                    FOR(k, mid + 1, SZ(idk))
                    {
                        if (idk[k] == T) x--;
                    }
                    if (i == T) x--;
                    if (x >= j + 1) hi = mid;
                    else lo = mid + 1;
                }
                ans[eid[i][idk[lo]]] = 1;
            }
        }
    }
    else
    {
        parent[0] = N; parent[N] = N;
        dfs(0, N);
        // FOR(i, 1, N)
        // {
        //     cerr << i << " -> " << parent[i] << endl;
        // }
        //1 = yes, -1 = no, 0 = idk
        FOR(ed, 0, M)
        {
            int u = e1[ed], v = e2[ed];
            if (depth[u] > depth[v]) swap(u, v);
            if (u == parent[v]) continue;
            //lol there are no side edges.
            vi nodes; nodes.PB(v);
            while(nodes.back() != u)
            {
                nodes.PB(parent[nodes.back()]);
            }
            assert(nodes.back() == u);
            //you know the answer?
            int s = -1;
            FOR(i, 0, SZ(nodes) - 1)
            {
                if (ans[eid[nodes[i]][nodes[i + 1]]] != -1)
                {
                    s = nodes[i];
                    break;
                }
            }
            if (s == -1)
            {
                int mn = get(0, 0), mx = mn;
                FOR(i, 0, SZ(nodes) - 1)
                {
                    int x = get(nodes[i], ed);
                    ckmin(mn, x);
                    ckmax(mx, x);
                }
                FOR(i, 0, SZ(nodes) - 1)
                {
                    int x = get(nodes[i], ed);
                    ans[eid[nodes[i]][nodes[i + 1]]] = ((mn == mx || x == mx) ? 0 : 1);
                }
                int x = get(0, 0);
                ans[ed] = ((mn == mx || x == mx) ? 0 : 1);
            }
            else
            {
                int x = get(s, ed);
                int y = get(0, 0);
                //y + ed - s = x -> ed = x + s - y
                ans[ed] = x + ans[eid[s][parent[s]]] - y;
                FOR(i, 0, SZ(nodes) - 1)
                {
                    int ed1 = eid[nodes[i]][nodes[i + 1]];
                    if (ans[ed1] != -1) continue;
                    x = get(nodes[i], ed);
                    //x = y + ed - ed1
                    ans[ed1] = y - x + ans[ed];
                }
            }
        }
        FOR(u, 1, N)
        {
            if (ans[eid[u][parent[u]]] == -1)
            {
                ans[eid[u][parent[u]]] = 1;
            }
        }
    }
    FOR(i, 0, M)
    {
        assert(ans[i] == 0 || ans[i] == 1);
        if (ans[i] == 1) ret.PB(i);
    }
    // cerr << "RETURNS:";
    // for (int x : ret)
    // {
    //     cerr << ' ' << x;
    // }
    // cerr << endl;
    return ret;
}

Compilation message

simurgh.cpp: In function 'vi find_roads(int, vi, vi)':
simurgh.cpp:121:9: error: 'Q' was not declared in this scope
     if (Q != 30000)
         ^