이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include "advisor.h"
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
const int MAXN = 1e5;
static int *C, N, K, M, B, D[MAXN+10], P[MAXN+10];
static vector<int> T[MAXN+10];
void ComputeAdvice(int *_C, int _N, int _K, int _M)
{
int i, j;
C=_C; N=_N; K=_K; M=_M;
for(i=20; i>=0; i--) if(N&(1<<i)) break;
B=i+1;
for(i=N-1; i>=0; i--) T[C[i]].push_back(i);
set<pii, greater<pii>> PQ;
for(i=0; i<K; i++)
{
if(T[i].empty()) PQ.insert({N, i});
else PQ.insert({T[i].back(), i}), T[i].pop_back();
P[i]=1;
}
for(i=0; i<N; i++)
{
if(P[C[i]])
{
PQ.erase({C[i], i});
if(T[C[i]].empty()) PQ.insert({N, C[i]});
else PQ.insert({T[C[i]].back(), C[i]}), T[C[i]].pop_back();
D[i]=(1<<B)-1;
}
else
{
D[i]=PQ.begin()->second;
P[PQ.begin()->second]=0;
PQ.erase(PQ.begin());
if(T[C[i]].empty()) PQ.insert({N, C[i]});
else PQ.insert({T[C[i]].back(), C[i]}), T[C[i]].pop_back();
}
}
for(i=0; i<N; i++)
{
for(j=0; j<B; j++)
{
if(D[i]&(1<<j)) WriteAdvice(1);
else WriteAdvice(0);
}
}
}
#include "assistant.h"
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
const int MAXN = 1e5;
static int N, K, R, B, D[MAXN+10];
unsigned char *A;
void Assist(unsigned char *_A, int _N, int _K, int _R)
{
int i, j;
A=_A; N=_N; K=_K; R=_R;
for(i=20; i>=0; i--) if(N&(1<<i)) break;
B=i+1;
int cnt=0;
for(i=0; i<N; i++) for(j=0; j<B; j++) if(A[cnt++]) D[i]|=(1<<j);
for(i=0; i<N; i++)
{
GetRequest();
if(D[i]!=(1<<B)-1) PutBack(D[i]);
}
}
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