제출 #168860

#제출 시각아이디문제언어결과실행 시간메모리
168860srvltGrowing Vegetable is Fun 3 (JOI19_ho_t3)C++14
60 / 100
7 ms4088 KiB
//#pragma GCC target ("avx2,sse2") //#pragma GCC optimization ("Ofast") //#pragma GCC optimization ("unroll-loops") #include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> using namespace __gnu_pbds; #define ordered_set tree <pair <ll, int>, null_type, less <pair <ll, int> >, rb_tree_tag, tree_order_statistics_node_update> #define ll long long #define ull unsigned long long #define db double #define pb push_back #define pf push_front #define ppb pop_back #define ppf pop_front #define fi first #define se second #define mp make_pair #define up_b upper_bound #define low_b lower_bound #define sz(x) (int)(x).size() #define all(x) (x).begin(), (x).end() #define endl "\n" #define left fsdsdfoisf #define sum dpsdfioppsf #define assign xcvjlkdjfio #define trie fksdfkjkfnjuiv #define next sidlfjsfkl #define merge sdfksdkfsldf //#define int long long using namespace std; void dout() { cerr << endl; } template <typename Head, typename... Tail> void dout(Head H, Tail... T) { cerr << H << ' '; dout(T...); } //mt19937 rng(chrono::steady_clock::now().time_since_epoch().count()); typedef pair <int, int> pii; const int N = 63, inf = 1e9; int n, dp[N][N][N][3], R, G, Y; vector <int> r, g, y; string s; void upd(int & x, int y) { x = min(x, y); } void solve(int tc) { // check for (int i = 0; i < n; j++) cin >> n >> s; for (int i = 1; i <= n; i++) { if (s[i - 1] == 'R') { r.pb(i); } else if (s[i - 1] == 'G') { g.pb(i); } else { y.pb(i); } } R = sz(r), G = sz(g), Y = sz(y); for (int i = 1; i <= n; i++) { for (int j = 0; j <= min(i, R); j++) { for (int k = 0; k <= min(i - j, G); k++) { int l = i - j - k; if (l > Y) { continue; } for (int h = 0; h < 3; h++) { dp[j][k][l][h] = inf; } if (j > 0) { upd(dp[j][k][l][0], dp[j - 1][k][l][1]); upd(dp[j][k][l][0], dp[j - 1][k][l][2]); int cnt = 0; for (int h = 0; h < k; h++) { if (g[h] > r[j - 1]) { cnt++; } } for (int h = 0; h < l; h++) { if (y[h] > r[j - 1]) { cnt++; } } dp[j][k][l][0] += abs(r[j - 1] + cnt - i); } if (k > 0) { upd(dp[j][k][l][1], dp[j][k - 1][l][0]); upd(dp[j][k][l][1], dp[j][k - 1][l][2]); int cnt = 0; for (int h = 0; h < j; h++) { if (r[h] > g[k - 1]) { cnt++; } } for (int h = 0; h < l; h++) { if (y[h] > g[k - 1]) { cnt++; } } dp[j][k][l][1] += abs(g[k - 1] + cnt - i); } if (l > 0) { upd(dp[j][k][l][2], dp[j][k][l - 1][0]); upd(dp[j][k][l][2], dp[j][k][l - 1][1]); int cnt = 0; for (int h = 0; h < j; h++) { if (r[h] > y[l - 1]) { cnt++; } } for (int h = 0; h < k; h++) { if (g[h] > y[l - 1]) { cnt++; } } dp[j][k][l][2] += abs(y[l - 1] + cnt - i); } } } } int res = inf; for (int i = 0; i < 3; i++) { upd(res, dp[R][G][Y][i]); } if (res == inf) { res = -1; } cout << res; } signed main() { ios_base::sync_with_stdio(false); cin.tie(NULL); // freopen("input.txt", "r", stdin); // freopen("output.txt", "w", stdout); int tc = 1; // cin >> tc; for (int i = 0; i < tc; i++) { solve(i); // cleanup(); } }
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