이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#pragma GCC optimize ("O2")
#pragma GCC optimize ("unroll-loops")
//#pragma GCC optimize("no-stack-protector,fast-math")
using namespace std;
typedef long long ll;
typedef long double ld;
typedef pair<int, int> pii;
typedef pair<pii, int> piii;
typedef pair<ll, ll> pll;
#define debug(x) cerr<<#x<<'='<<(x)<<endl;
#define debugp(x) cerr<<#x<<"= {"<<(x.first)<<", "<<(x.second)<<"}"<<endl;
#define debug2(x, y) cerr<<"{"<<#x<<", "<<#y<<"} = {"<<(x)<<", "<<(y)<<"}"<<endl;
#define debugv(v) cerr<<#v<<" : ";for (auto x:v) cerr<<x<<' ';cerr<<endl;
#define all(x) x.begin(), x.end()
#define pb push_back
#define kill(x) return cout<<x<<'\n', 0;
const ld eps=1e-7;
const int inf=1000000010;
const ll INF=10000000000000010LL;
const int mod = 1000000007;
const int MAXN = 100010, Base=10007, Mod=1e9+9;
int n, m, k, u, v, x, y, t, a, b;
int A[MAXN];
string s;
void solve(){
cin>>s;
int ans=0;
ll h1=0, h2=0, tav=1;
n=s.size();
for (int i=0; i<n-i-1; i++){
h1=(h1*Base + (s[i]-'a'+1))%Mod;
h2=((s[n-i-1]-'a'+1)*tav + h2)%Mod;
tav=tav*Base%Mod;
if (h1==h2){
ans+=2;
h1=h2=0;
tav=1;
}
}
if (h1!=h2 || n&1) ans++;
cout<<ans<<'\n';
}
int main(){
ios_base::sync_with_stdio(false);cin.tie(0);cout.tie(0);
//freopen("input.txt", "r", stdin);
//freopen("output.txt", "w", stdout);
int T;
cin>>T;
while (T--) solve();
return 0;
}
/*
4
bonobo
deleted
racecar
racers
1
abcdcba
*/
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