이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#include "vision.h"
using namespace std;
vector<int> checkBlock(vector<int> &a, vector<int> &b, int K) {
vector<int> res;
for (int i = K-1; i < int(a.size()); i++) {
vector<int> g, h;
for (int j = i - K + 1; j <= i; j++) {
h.emplace_back(b[j]);
g.emplace_back(a[j]);
}
res.emplace_back(add_and({ add_or(g), add_or({ add_or(h), add_and({ add_not(add_or(h)), add_not(add_xor(g)) }) }) }));
}
return res;
}
void construct_network(int H, int W, int K) {
vector<int> lefDi1, rigDi1;
vector<int> lefDi2, rigDi2;
// step 1 + 2: right diagonal
for (int i = H-1; i >= 0; i--) {
vector<int> a;
for (int x = i, y = 0; x < H && y < W; x++, y++) a.emplace_back(x * W + y);
int g = add_xor(a);
rigDi1.emplace_back(g);
rigDi2.emplace_back( add_and( {add_not(g), add_or(a)} ) );
}
for (int i = 1; i < W; i++) {
vector<int> a;
for (int x = 0, y = i; x < H && y < W; x++, y++) a.emplace_back(x * W + y);
int g = add_xor(a);
rigDi1.emplace_back(g);
rigDi2.emplace_back( add_and( {add_not(g), add_or(a)} ) );
}
// step 1 + 2: left diagonal
for (int i = 0; i < W; i++) {
vector<int> a;
for (int x = 0, y = i; x < H && y >= 0; x++, y--) a.emplace_back(x * W + y);
int g = add_xor(a);
lefDi1.emplace_back(g);
lefDi2.emplace_back( add_and( {add_not(g), add_or(a)} ) );
}
for (int i = 1; i < H; i++) {
vector<int> a;
for (int x = i, y = W-1; x < H && y >= 0; x++, y--) a.emplace_back(x * W + y);
int g = add_xor(a);
lefDi1.emplace_back(g);
lefDi2.emplace_back( add_and( {add_not(g), add_or(a)} ) );
}
// step 3-4-5:
int g = add_and({ add_or(checkBlock(lefDi1, lefDi2, K+1)), add_or(checkBlock(rigDi1, rigDi2, K+1)) });
// step 6:
int h = add_and({ add_or(checkBlock(lefDi1, lefDi2, K)), add_or(checkBlock(rigDi1, rigDi2, K)) });
// step 7:
add_and({ g, add_not(h) });
}
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