제출 #161649

#제출 시각아이디문제언어결과실행 시간메모리
161649arnold518구슬과 끈 (APIO14_beads)C++14
0 / 100
6 ms5240 KiB
#include <bits/stdc++.h> using namespace std; typedef long long ll; typedef pair<int, int> pii; typedef pair<ll, ll> pll; const int MAXN = 2e5; const ll INF = 1e15; int N; vector<pii> adj[MAXN+10]; ll dp1[MAXN+10], dp2[MAXN+10], dp3[MAXN+10], dp4[MAXN+10], len[MAXN+10], ans; void dfs(int now, int bef, ll par) { ll val=0; len[now]=par; for(pii nxt : adj[now]) { if(nxt.first==bef) continue; dfs(nxt.first, now, nxt.second); dp2[now]+=dp1[nxt.first]; val=max(val, par-dp1[nxt.first]+dp2[nxt.first]+nxt.second); } dp1[now]=dp2[now]+val; //printf("%d %lld %lld\n", now, dp1[now], dp2[now]); } void dfs2(int now, int bef) { ll val=0; dp4[now]=dp2[bef]-dp1[now]+dp3[bef]; for(pii nxt : adj[bef]) { if(nxt.first==now) continue; val=max(val, -dp1[nxt.first]+dp2[nxt.first]+len[nxt.first]+len[now]); } dp3[now]=dp2[bef]-dp1[now]+dp3[bef]+val; dp3[now]=max(dp3[now], dp2[bef]-dp1[now]+dp4[bef]+len[now]+len[bef]); if(now==1) dp3[now]=dp4[now]=0; for(pii nxt : adj[now]) { if(nxt.first==bef) continue; dfs2(nxt.first, now); } } int main() { int i, j; scanf("%d", &N); for(i=1; i<N; i++) { int u, v, w; scanf("%d%d%d", &u, &v, &w); adj[u].push_back({v, w}); adj[v].push_back({u, w}); } dfs(1, 0, -INF); dfs2(1, 0); for(i=1; i<=N; i++) ans=max(ans, dp2[i]+dp3[i]); printf("%lld", ans); }

컴파일 시 표준 에러 (stderr) 메시지

beads.cpp: In function 'int main()':
beads.cpp:51:12: warning: unused variable 'j' [-Wunused-variable]
     int i, j;
            ^
beads.cpp:53:10: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
     scanf("%d", &N);
     ~~~~~^~~~~~~~~~
beads.cpp:57:14: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
         scanf("%d%d%d", &u, &v, &w);
         ~~~~~^~~~~~~~~~~~~~~~~~~~~~
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