| # | Time | Username | Problem | Language | Result | Execution time | Memory |
|---|---|---|---|---|---|---|---|
| 158601 | oolimry | 말 (IOI15_horses) | C++14 | 1560 ms | 91164 KiB |
This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include "horses.h"
#include <bits/stdc++.h>
using namespace std;
long long mod = 1000000007;
long long x[500005];
long long y[500005];
long double lnx[500005];
long double lny[500005];
typedef pair<long double, int> ii;
class Segtree{
public:
int n;
vector<ii> tree;
vector<long double> lazy;
void create(int nn){
n = nn;
for(int i = 0;i < 2*n+5;i++){
tree.push_back(ii(0.0,0));
lazy.push_back(0.0);
}
long double acc = 0.0;
for(int i = 0;i < n;i++){
acc += lnx[i];
tree[i+n] = ii(acc+lny[i],i);
}
for(int i = n-1;i >= 1;i--){
tree[i] = max(tree[i<<1],tree[i<<1|1]);
}
}
int query(){
return tree[1].second;
}
void update(int l, int r, long double v){
int ll = l + n; int rr = r + n;
for(l += n, r += n;l < r;l >>= 1, r >>= 1){
if(l&1){
lazy[l] += v;
tree[l].first += v;
l++;
}
if(r&1){
r--;
lazy[r] += v;
tree[r].first += v;
}
}
while(ll > 1){
ll >>= 1;
ii x = max(tree[ll<<1],tree[ll<<1|1]);
tree[ll] = ii(x.first + lazy[ll], x.second);
}
while(rr > 1){
rr >>= 1;
ii x = max(tree[rr<<1],tree[rr<<1|1]);
tree[rr] = ii(x.first + lazy[rr], x.second);
}
}
};
int n;
Segtree seg;
long long answer(){
int pos = seg.query();
long long value = 1;
for(int i = 0;i <= pos;i++){
value *= x[i];
value %= mod;
}
value *= y[pos];
value %= mod;
return value;
}
int init(int N, int X[], int Y[]) {
n = N;
for(int i = 0;i < N;i++){
x[i] = X[i];
y[i] = Y[i];
lnx[i] = (double)log2((double)X[i]);
lny[i] = (double)log2((double)Y[i]);
//printf("%f %f\n",lnx[i],lny[i]);
}
seg.create(n);
return answer();
}
int updateX(int pos, int val) {
x[pos] = val;
long double oln = lnx[pos];
lnx[pos] = (double)log2((double)x[pos]);
oln = lnx[pos] - oln;
seg.update(pos,n,oln);
return answer();
}
int updateY(int pos, int val) {
y[pos] = val;
long double oln = lny[pos];
lny[pos] = (double)log((double)y[pos]);
oln = lny[pos] - oln;
seg.update(pos,pos+1,oln);
return answer();
}
Compilation message (stderr)
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