답안 #15569

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
15569	2015-07-12T23:58:39 Z	ainta	통로 위의 개미 (kriii3_X)	C++	0 / 85	300 ms	524288 KB

X

#include<stdio.h>
#include<algorithm>
using namespace std;
struct SegTree{
    SegTree *c1, *c2;
    int S;
    SegTree(){
        c1=c2=NULL;
        S=0;
    }
};
long long L;
int cnt, n, Q;
struct Query{
    long long b, e;
}w[5];
void AddQ(long long b, long long e){
    if(b<0)b+=2*L,e+=2*L;
    b%=(2*L),e%=(2*L);
    if(b>e)e+=2*L;
    if(e>=2*L){
        w[cnt].b=b,w[cnt].e=2*L-1;cnt++;
        w[cnt].b=0,w[cnt].e=e-2*L;cnt++;
        return;
    }
    w[cnt].b=b,w[cnt].e=e;cnt++;
}
SegTree *Root;

void Ins(SegTree *nd, int b, int e, int x, int y){
    if(b==e){
        nd->S+=y;
        return;
    }
    int m = (b+1)/2+e/2;
    if(x <= m){
        if(!nd->c1)nd->c1 = new SegTree();
        Ins(nd->c1,b,m,x,y);
    }
    else{
        if(!nd->c2)nd->c2 = new SegTree();
        Ins(nd->c2,m+1,e,x,y);
    }
    nd->S=0;
    if(nd->c1)nd->S += nd->c1->S;
    if(nd->c2)nd->S += nd->c2->S;
}

int Gap(SegTree *nd, int b, int e, int s, int l){
    if(b==s&&e==l){
        return nd->S;
    }
    int m = (b+1)/2+e/2, r = 0;
    if(nd->c1 && s <= m)r += Gap(nd->c1,b,m,s,min(m,l));
    if(nd->c2 && l > m)r += Gap(nd->c2,m+1,e,max(m+1,s),l);
    return r;
}

int Pro(long long mid, long long t){
    long long s = 0;
    cnt = 0;
    if(mid < L){
        AddQ(-t,-t+mid);
        if(mid)AddQ(2*L-mid-t,2*L-t-1);
    }
    else if(mid > L){
        AddQ(-t,-t+2*L-mid);
        AddQ(-t+mid,-t+L*2-1);
    }
    else AddQ(0,2*L-1);
    s=0;
    for(int i=0;i<cnt;i++){
        s += Gap(Root,0,2*L-1,w[i].b,w[i].e);
    }
    return s;
}

int Rank[601][1010], In[201000], SZ[601], MM;
int TP[201000];

void init(){
    int i, j, cnt = 0, pv = 1, tt;
    for(i=1;i<=MM;i++){
        for(j=1;j<=SZ[i];j++)TP[++cnt]=Rank[i][j];
        SZ[i]=0;
    }
    tt = (cnt-1)/600+1;
    for(i=1;i<=cnt;i++){
        if(SZ[pv] == tt)pv++;
        Rank[pv][++SZ[pv]] = TP[i];
        In[TP[i]]=pv;
    }
    MM = pv;
}

void UDT(int a, int r){
    if(!MM){
        MM++;
        Rank[1][++SZ[1]] = a;
        In[a] = 1;
        return;
    }
    int i, x, rr = r;
    for(i=1;i<=MM;i++){
        if(SZ[i]+1>=r)break;
        r-=SZ[i];
    }
    x = i;
    if(SZ[x] == 800){
        init();
        UDT(a,rr);
        return;
    }
    for(i=SZ[x];i>=r;i--)Rank[x][i+1]=Rank[x][i];
    Rank[x][r] = a;
    SZ[x]++;
    In[a] = x;
}

int Get(int a){
    int x = In[a], i, c = 0;
    for(i=1;i<x;i++)c+=SZ[i];
    for(i=1;i<=SZ[x];i++){
        if(Rank[x][i]==a)break;
    }
    return c+i;
}

int main(){
    int r, p, b;
    long long t,be, ed, mid;
    long long a;
    scanf("%lld%d",&L,&Q);
    Root = new SegTree();
    while(Q--){
        scanf("%lld%d%lld",&t,&p,&a);
        t%=(2*L);
        if(p==1){
            scanf("%d",&b);
            if(b == -1)a = 2*L-a;
            n++;
            UDT(n, Pro(a,t)+1);
            a=(a-t+2*L)%(2*L);
            Ins(Root, 0, 2*L-1, a, 1);
        }
        if(p==2){
            a = Get(a);
            be = 0, ed = L-1, r = L;
            while(be<=ed){
                mid=(be+ed)>>1;
                if(Pro(mid,t) >= a){
                    r= mid;
                    ed=mid-1;
                }
                else be=mid+1;
            }
            printf("%d\n",r);
        }
    }
}

Subtask #1

0.0 / 30.0

#	결과	실행 시간	메모리	Grader output
1	Memory limit exceeded	300 ms	524288 KB	Memory limit exceeded
2	Halted	0 ms	0 KB	-

Subtask #2

0.0 / 55.0

#	결과	실행 시간	메모리	Grader output
1	Halted	0 ms	0 KB	-