제출 #154382

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
154382		arnold518	조교 (CEOI16_popeala)	C++14	26 / 100	2037 ms	8568 KiB

popeala

#include <bits/stdc++.h>
using namespace std;

typedef long long ll;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;

const int MAXN = 50;
const int MAXT = 20000;
const ll INF = 1e15;

int N, T, S, P[MAXT+10], R[MAXN+10][MAXT+10];
vector<int> V[MAXT+10];
int cnt[MAXN+10];
ll dp[MAXN+10][MAXT+10];

int main()
{
    int i, j, k, p;

    scanf("%d%d%d", &N, &T, &S);
    for(i=1; i<=T; i++) scanf("%d", &P[i]), P[i]+=P[i-1];
    for(i=1; i<=N; i++) for(j=1; j<=T; j++) scanf("%1d", &R[i][j]);

    for(i=1; i<=T; i++)
    {
        for(j=1; j<=N; j++) if(R[j][i]==0) cnt[j]=i;
        for(j=1; j<=N; j++) V[i].push_back(cnt[j]);
        V[i].push_back(i); V[i].push_back(0);
        sort(V[i].begin(), V[i].end());
        //for(j=0; j<=N+1; j++) printf("%d ", V[i][j]); printf("\n");
    }

    for(i=0; i<=S; i++) for(j=0; j<=T; j++) dp[i][j]=INF;
    dp[0][0]=0;
    for(i=1; i<=S; i++)
    {
        for(k=0; k<=N; k++)
        {
            for(j=1; j<=T; j++)
            {
                ll now=INF;
                for(p=V[j][k]; p<V[j][k+1]; p++) now=min(now, dp[i-1][p]+k*P[j]-k*P[p]);
                dp[i][j]=min(dp[i][j], now);
            }
        }
    }
    for(i=1; i<=S; i++) printf("%lld\n", dp[i][T]);
}

컴파일 시 표준 에러 (stderr) 메시지

popeala.cpp: In function 'int main()':
popeala.cpp:21:10: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
     scanf("%d%d%d", &N, &T, &S);
     ~~~~~^~~~~~~~~~~~~~~~~~~~~~
popeala.cpp:22:43: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
     for(i=1; i<=T; i++) scanf("%d", &P[i]), P[i]+=P[i-1];
                         ~~~~~~~~~~~~~~~~~~^~~~~~~~~~~~~~
popeala.cpp:23:50: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
     for(i=1; i<=N; i++) for(j=1; j<=T; j++) scanf("%1d", &R[i][j]);
                                             ~~~~~^~~~~~~~~~~~~~~~~

• Subtask 1: 8 / 8
• Subtask 2: 9 / 9
• Subtask 3: 9 / 9
• Subtask 4: 0 / 74