Submission #143316

#	Time	Username	Problem	Language	Result	Execution time	Memory
143316		popovicirobert	Sailing Race (CEOI12_race)	C++14	5 / 100	3055 ms	2808 KiB

race

#include <bits/stdc++.h>
#define lsb(x) (x & (-x))
#define ll long long
#define ull unsigned long long



/*const int MOD = ;

inline int lgput(int a, int b) {
    int ans = 1;
    while(b > 0) {
        if(b & 1) ans = (1LL * ans * a) % MOD;
        b >>= 1;
        a = (1LL * a * a) % MOD;
    }
    return ans;
}

inline void mod(int &x) {
    if(x >= MOD)
        x -= MOD;
}

inline void add(int &x, int y) {
    x += y;
    mod(x);
}

inline void sub(int &x, int y) {
    x += MOD - y;
    mod(x);
}

inline void mul(int &x, int y) {
    x = (1LL * x * y) % MOD;
}

inline int inv(int x) {
    return lgput(x, MOD - 2);
}*/

/*int fact[], invfact[];

inline void prec(int n) {
    fact[0] = 1;
    for(int i = 1; i <= n; i++) {
        fact[i] = (1LL * fact[i - 1] * i) % MOD;
    }
    invfact[n] = lgput(fact[n], MOD - 2);
    for(int i = n - 1; i >= 0; i--) {
        invfact[i] = (1LL * invfact[i + 1] * (i + 1)) % MOD;
    }
}

inline int comb(int n, int k) {
    if(n < k) return 0;
    return (1LL * fact[n] * (1LL * invfact[k] * invfact[n - k] % MOD)) % MOD;
}*/

using namespace std;

const int INF = 1e9;
const int MAXN = 500;

int dp[MAXN][MAXN][2];
int best[MAXN];

int main() {
#if 0
    ifstream cin("A.in");
    ofstream cout("A.out");
#endif
    int i, j, n, k;
    ios::sync_with_stdio(false);
    cin.tie(0), cout.tie(0);

    cin >> n >> k;
    vector < vector <int> > g(n);
    for(i = 0; i < n; i++) {
        int x;
        cin >> x;
        while(x != 0) {
            x--;
            g[i].push_back(x);
            cin >> x;
        }
    }

    for(int len = 1; len < n; len++) {
        for(i = 0; i + len < n; i++) {
            j = i + len;
            for(auto k : g[i]) {
                if(i < k && k < j) {
                    dp[i][j][0] = max(dp[i][j][0], 1 + max(dp[i][k][1], dp[k][j][0]));
                }
            }
            for(auto k : g[j]) {
                if(i < k && k < j) {
                    dp[i][j][1] = max(dp[i][j][1], 1 + max(dp[i][k][1], dp[k][j][0]));
                }
            }
        }
        for(j = 0; j + len < n; j++) { //i > j
            i = j + len;
            for(auto k : g[i]) {
                if(k < j || k > i) {
                    dp[i][j][0] = max(dp[i][j][0], 1 + max(dp[i][k][1], dp[k][j][0]));
                }
            }
            for(auto k : g[j]) {
                if(k < j || k > i) {
                    dp[i][j][1] = max(dp[i][j][0], 1 + max(dp[i][k][1], dp[k][j][0]));
                }
            }
        }
    }

    auto combine = [&](pair <int, int> &ans, pair <int, int> cur) {
        if(ans.first < cur.first) {
            swap(ans, cur);
        }
    };

    pair <int, int> ans = {0, 0};
    for(i = 0; i < n; i++) {
        for(j = 0; j < n; j++) {
            combine(ans, {dp[i][j][0], i});
            combine(ans, {dp[i][j][1], j});
        }
    }
    if(k == 0) {
        cout << ans.first << "\n" << ans.second + 1;
        return 0;
    }

    auto prv = [&](int x) {
        return (x == 0 ? n - 1 : x - 1);
    };
    auto nxt = [&](int x) {
        return (x == n - 1 ? 0 : x + 1);
    };

    for(i = 0; i < n; i++) {
        for(auto j : g[i]) {
            fill(best, best + n, -INF);
            best[j] = 0;
            for(int k = j; k != i; k = nxt(k)) {
                for(auto it : g[k]) {
                    best[it] = max(best[it], best[k] + 1);
                }
                for(auto it : g[k]) {
                    if((i < j && i <= it && it <= j) || (i > j && (it >= i || it <= j))) continue;
                    combine(ans, {2 + best[k] + max(dp[it][j][0], dp[i][it][1]), i});
                }
            }

            fill(best, best + n, -INF);
            best[j] = 0;
            for(int k = j; k != i; k = prv(k)) {
                for(auto it : g[k]) {
                    best[it] = max(best[it], best[k] + 1);
                }
                for(auto it : g[k]) {
                    if((i < j && i <= it && it <= j) || (i > j && (it >= i || it <= j))) continue;
                    combine(ans, {2 + best[k] + max(dp[it][i][0], dp[j][it][1]), i});
                }
            }
        }
    }
    cout << ans.first << "\n" << ans.second  + 1;


    return 0;
}

• Subtask 1: 5 / 100