제출 #1321750

#제출 시각아이디문제언어결과실행 시간메모리
1321750benjaminkleyn이주 (IOI25_migrations)C++20
30 / 100
31 ms1448 KiB
#include "migrations.h" #include <bits/stdc++.h> using namespace std; int n; int P[10000]; vector<int> g[10000]; int dist[10000] = {0}; void dfs(int u, int p = -1) { if (p == -1) dist[u] = 0; for (int v : g[u]) if (v != p) { dist[v] = dist[u] + 1; dfs(v, u); } } int prev_a, prev_b; int a, b; void find_diameter() { prev_a = a; prev_b = b; a = b = 0; dfs(0); for (int i = 0; i < n; i++) if (dist[i] > dist[a]) a = i; // dfs(a); // for (int i = 0; i < n; i++) // if (dist[i] > dist[b]) // b = i; } bool cancelled = false; int send_message(int N, int i, int Pi) { n = N; g[i].push_back(Pi); g[Pi].push_back(i); if (i >= N - 8) { find_diameter(); if (a == i) { cancelled = true; return 0; } if (cancelled) { return 1; } int shift_amount = 2 * (N - 1 - i); return ((a >> shift_amount) & 0b11) + 1; } return 0; } pair<int, int> longest_path(vector<int> S) { int N = S.size(); int res = 0; for (int i = N - 1; i >= N - 8; i--) { if (S[i] == 0) return {0, i}; int shift_amount = 2 * (N - 1 - i); res |= (S[i] - 1) << shift_amount; } return {0, res}; }
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