제출 #1313174

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
1313174		Tymond	상형문자열 (IOI24_hieroglyphs)	C++20	3 / 100	472 ms	38752 KiB

hieroglyphs

#include "hieroglyphs.h"
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
using ld = long double;
#define fi first
#define se second
#define vi vector<int>
#define vll vector<long long>
#define pii pair<int, int>
#define pll pair<long long, long long>
#define pb push_back
#define mp make_pair
#define eb emplace_back
#define all(x) (x).begin(), (x).end()
#define sz(x) (int)(x).size()
mt19937 rng(chrono::high_resolution_clock::now().time_since_epoch().count());
mt19937_64 rng64(chrono::high_resolution_clock::now().time_since_epoch().count());
inline int rand(int l,int r){return uniform_int_distribution<int>(l, r)(rng);}
inline ll rand(ll l,ll r){return uniform_int_distribution<ll>(l, r)(rng64);}
#ifdef DEBUG
auto&operator<<(auto&o,pair<auto,auto>p){return o<<"("<<p.first<<", "<<p.second<<")";}
auto operator<<(auto&o,auto x)->decltype(x.end(),o){o<<"{";int i=0;for(auto e:x)o<<","+!i++<<e;return o<<"}";}
#define debug(X...)cerr<<"["#X"]: ",[](auto...$){((cerr<<$<<"; "),...)<<endl;}(X)
#else
#define debug(...){}
#endif

bool check_one(vi a, vi b){
    int n = sz(a);
    int m = sz(b);
    int cntA[2] = {0, 0};
    int cntB[2] = {0, 0};
    for(auto ele : a){
        cntA[ele]++;
    }

    for(auto ele : b){
        cntB[ele]++;
    }

    if(cntA[0] > cntB[0] || (cntA[0] == cntB[0] && cntA[1] > cntB[1])){
        swap(a, b);
        swap(n, m);
        swap(cntA[0], cntB[0]);
        swap(cntA[1], cntB[1]);
    }

    if(cntA[1] <= cntB[1]){
        int wsk = 0;
        for(auto ele : b){
            if(wsk == n){
                return true;
            }
            if(ele == a[wsk]){
                wsk++;
            }
        }
        if(wsk == n){
            return true;
        }
        return false;
    }
 //   debug(a);
 //   debug(b);
    int wska = 0;
    int wskb = 0;
    int cnt = 0;
    int target = cntA[0] + cntB[1];
    int curr[2] = {0, 0};
    int t[2] = {cntA[0], cntB[1]};
    while(cnt < target){
      //  cerr << wska << ' ' << wskb << ' ' << cnt << '\n';
        if(wska == n || wskb == m){
            return false;
        }
        if(a[wska] == b[wskb]){
            cnt++;
            cntA[a[wska]]--;
            cntB[b[wskb]]--;
            wska++;
            wskb++;
            continue;
        }

        if(curr[a[wska]] + cntA[a[wska]] == t[a[wska]]){
            cntB[b[wskb]]--;
            wskb++;
        }else{
            cntA[a[wska]]--;
            wska++;
        }
    }

    return true;
}

vi ucs(vi A, vi B){
    int n = sz(A);
    int m = sz(B);
    vi ret = {-1};
    for(int b = 0; b < 19; b++){
        vi na = {};
        vi nb = {};
        for(auto ele : A){
            if(ele & (1 << b)){
                na.pb(1);
            }else{
                na.pb(0);
            }
        }

        for(auto ele : B){
            if(ele & (1 << b)){
                nb.pb(1);
            }else{
                nb.pb(0);
            }
        }
        //debug(b);
        //debug(na);
       // debug(nb);

        if(!check_one(na, nb)){
            return ret;
        }
    }
    ret = {};
    //znajdź wynik
    set<int> ind = {};
    map<int, vi> posA;
    map<int, vi> posB;
    map<int, int> cntA;
    map<int, int> cntB;
    for(int i = n - 1; i >= 0; i--){
        posA[A[i]].pb(i);
        cntA[A[i]]++;
    }
    for(int i = m - 1; i >= 0; i--){
        posB[B[i]].pb(i);
        cntB[B[i]]++;
    }
    
    int mx = -1;
    for(int i = 0; i < n; i++){
        if(cntA[A[i]] > cntB[A[i]]){
            continue;
        }

        while(sz(posB[A[i]]) && posB[A[i]].back() <= mx){
            posB[A[i]].pop_back();
        }
        ind.insert(i);
        mx = posB[A[i]].back();
        posB[A[i]].pop_back();
    }

    mx = -1;
    for(int i = 0; i < m; i++){
        if(cntB[B[i]] > cntA[B[i]]){
            continue;
        }

        while(sz(posA[B[i]]) && posA[B[i]].back() <= mx){
            posA[B[i]].pop_back();
        }
        ind.insert(posA[B[i]].back());
        mx = posA[B[i]].back();
        posA[B[i]].pop_back();
    }

    for(auto ele : ind){
        ret.pb(A[ele]);
    }

    return ret;
}

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